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Appian Exam ACD101 Topic 5 Question 31 Discussion

Actual exam question for Appian's ACD101 exam
Question #: 31
Topic #: 5
[All ACD101 Questions]

Review the following expression rule:

union(ri!fruit, ri!vegetables)

The rule inputs are configured as text arrays.

What is the expected output?

Show Suggested Answer Hide Answer
Suggested Answer: B

The best practice in Appian for passing values into an interface is to use named parameters, which is demonstrated by Option B. Named parameters make the code more readable and maintainable by clearly specifying which parameter each value is being passed to. In this case, the recordId and firstName parameters are clearly being assigned the values 1 and 'Kyle' respectively. Reference:

Appian Documentation: Passing Parameters to Interfaces


Contribute your Thoughts:

Maile
13 days ago
Union? More like 'onion' - this question is making me cry!
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Edwin
14 days ago
Hmm, this is a tricky one. I'm leaning towards B, since the question mentions the rule 'union', which might have a different behavior than a regular union operation.
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Zoila
16 days ago
I'm going with C. The union operation should remove any duplicate values, so the output should be a combined list of all items from both arrays, without duplicates.
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Kristofer
23 days ago
I'm not sure about this one. The question talks about a 'rule', so I'm guessing the output might be different from a standard union operation. I'll have to think about it some more.
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Dulce
21 hours ago
A) All items in ri!fruit followed by items in ri!vegetables, including duplicate values.
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Viola
30 days ago
I think the answer is A. The union operation should combine the contents of the two arrays, even if there are duplicates.
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Kate
7 days ago
I'm not sure, but I think it might be B.
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Lennie
14 days ago
I think it's actually C, the duplicates are removed in the output.
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Precious
15 days ago
I agree, the answer is A.
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Deonna
1 months ago
I'm not sure, but I think the correct answer is B) Only items that are in both ri!fruit and ri!vegetables.
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Roslyn
1 months ago
I disagree, I believe the expected output is C) All items in ri!fruit and ri!vegetables combined, with duplicates removed.
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Pok
1 months ago
I think the expected output is A) All items in ri!fruit followed by items in ri!vegetables, including duplicate values.
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