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Adobe Exam AD0-E720 Topic 4 Question 15 Discussion

Actual exam question for Adobe's AD0-E720 exam
Question #: 15
Topic #: 4
[All AD0-E720 Questions]

An Adobe Commerce developer needs to display a URL in the template. How would the variable $ur1 be securely output in the template?

Show Suggested Answer Hide Answer
Suggested Answer: A, C

To apply a knockout binding to a

to run a function, onClick(), when it's clicked, the developer can use either of the following solutions:

A)

: This solution will use the click binding to execute the onClick() function as an expression when the
is clicked. The function will be called with the current binding context as the first parameter and the event object as the second parameter.

C)

: This solution will use the click binding to execute the onClick function as a reference when the
is clicked. The function will be called with the current binding context as the first parameter and the event object as the second parameter.

The following solutions are not valid and will not work:

B)

<!-- ko click: 'onClick' --><!-- /ko -->
: This solution will use the virtual element syntax to apply the click binding, but it will pass a string literal instead of a function expression or reference. This will cause an error, as the click binding expects a function value.

D)

: This solution will use a custom attribute instead of a data-bind attribute to apply the click binding. This is not supported by knockout and will not have any effect.


Contribute your Thoughts:

Kaitlyn
21 days ago
I was gonna go with D) and hope for the best. Guess that's not the Adobe way, huh?
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Sharita
24 days ago
Wait, there's an 'escaper' object? I was just going to echo the $url variable directly. Glad I checked the answers!
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Tran
2 days ago
User2: I think the correct option is A) escapeUrl($url) ?>
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Lang
3 days ago
User1: Yes, it's important to use the escaper object to securely output URLs in the template.
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Jamey
29 days ago
Hmm, I was thinking C) escapeHtml($url) ?>, but I guess that's not the right approach here. Thanks for the clarification!
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Dortha
3 days ago
User 2: B) escapeLink($url) ?>
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Shaunna
8 days ago
User 1: A) escapeUrl($url) ?>
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Jody
1 months ago
I was going to say B) escapeLink($url) ?>, but now I'm not so sure. Looks like A is the way to go for secure URL output.
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Gail
2 days ago
I think A) escapeUrl($url) ?> is the correct way to securely output the URL.
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Jacinta
1 months ago
The correct answer is A) escapeUrl($url) ?>. This is the most secure way to display a URL in a template, as it properly escapes the URL to prevent potential security vulnerabilities.
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Lenna
23 days ago
I think the answer is A) escapeUrl($url) ?>
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Loreta
2 months ago
I'm not sure, but I think C) escapeHtml($url) ?> could also be a valid option
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William
2 months ago
I agree with Loreta, because we need to escape the URL for security
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Loreta
2 months ago
I think the answer is A) escapeUrl($url) ?>
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