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Zend 200-710 Exam - Topic 8 Question 50 Discussion

Actual exam question for Zend's 200-710 exam
Question #: 50
Topic #: 8
[All 200-710 Questions]

What is the output of the following code?

function increment ($val)

{

++$val;

}

$val = 1;

increment ($val);

echo $val;

Show Suggested Answer Hide Answer
Suggested Answer: B

by Franklyn at Jul 28, 2023, 04:19 PM

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Jutta
6 months ago
That's correct, just a local increment.
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Ulysses
6 months ago
Yup, it's passed by value, so it stays the same.
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Marylyn
6 months ago
Wait, are you sure? I thought it would increment it!
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Tony
6 months ago
Totally agree, it doesn't change the original variable.
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Silvana
7 months ago
The output will be 1.
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Rosio
7 months ago
Wait, does the function modify the variable outside its scope? I'm confused if it affects the original value or not.
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Roselle
7 months ago
I practiced a question like this before, and I believe it also returned the original value. So, I'm leaning towards 1.
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Laurel
7 months ago
I'm not entirely sure, but I remember something similar where the original variable didn't change after the function call.
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Ludivina
7 months ago
I think the output will be 1 because the function increments a copy of the variable, not the original.
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Viva
7 months ago
This is a tricky one. I'm not entirely sure which option is the best fit, but I'll carefully consider each choice and try to eliminate the ones that don't seem to address the requirement.
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Mozell
7 months ago
I think the maximum tenant name length is 64 characters, but I'm not entirely sure. I need to double-check my notes.
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Therese
7 months ago
This reminds me of a practice question where we had to determine the best way to handle duplicate code. I think that creating a reusable service candidate could really streamline the process.
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Colette
8 months ago
Okay, let's think this through. The question mentions an "application-aware firewall", so that suggests it's looking at Layer 7 inspection. And the options talk about stateful vs. stateless inspection for TCP and UDP. I'm leaning towards option B, but I'll double-check my understanding.
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Sabina
12 months ago
Oh, I see. So the function is like a black box that just does its thing and doesn't give me back the new value. Time to brush up on my PHP function basics!
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Stefan
10 months ago
Jani: Exactly, it's important to remember how functions work in PHP.
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Meaghan
10 months ago
User 3: So the original value of $val remains unchanged.
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Jani
10 months ago
User 2: Yeah, the function just increments the value but doesn't return it.
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Daren
11 months ago
User 1: The output is 1.
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Tommy
12 months ago
I got this one! The output is 1 because the increment() function only modifies the local copy of $val, not the original variable. The echo statement outside the function still prints the original value of 1.
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Judy
1 year ago
Haha, this is a classic gotcha question! I remember seeing something similar in my last exam. The key is that the function doesn't return the incremented value, it just modifies the original variable. So the output will be 1.
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Joanna
11 months ago
I got tricked by that as well. It's 1.
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Simona
11 months ago
Definitely a common mistake to make.
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Joanna
11 months ago
Yeah, I fell for that one too. The output is 1.
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Britt
12 months ago
I always forget about passing by reference in PHP.
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Simona
12 months ago
Yeah, I fell for that one too. It's tricky!
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Ashley
1 year ago
Actually, the output is 1 because the increment function is not returning the updated value.
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Yesenia
1 year ago
I think the output is 2 because the increment function should increase the value by 1.
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Colby
1 year ago
Wait, why is the output not 1? Isn't the function just incrementing the value and then returning it? I'm confused.
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Raymon
11 months ago
That's why the output is still 1.
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Nana
11 months ago
So when you echo $val outside the function, it remains unchanged.
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Ruthann
11 months ago
The function is only changing the value locally within the function.
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Dusti
11 months ago
The function is incrementing the value, but it is not returning the updated value.
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Niesha
11 months ago
Got it, thanks for explaining!
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Shawna
11 months ago
Exactly, that's why the output is still 1.
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Dorothy
11 months ago
Oh, so the value of $val is not being changed outside of the function.
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Twana
11 months ago
The function is incrementing the value, but it's not returning the updated value.
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Ashley
1 year ago
The output is 1.
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Linette
1 year ago
Actually, the output is 1 because the function is not returning the incremented value.
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Georgeanna
1 year ago
The output will be 2. The increment operator (++) increments the value of $val by 1, so after calling the increment() function, the value of $val should be 2.
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Weldon
12 months ago
Yes, it will be 2.
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Rachael
12 months ago
No, it will be 1.
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Mary
1 year ago
The output will be 2.
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Dylan
1 year ago
The output will be 1.
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Lura
1 year ago
I think the output will be 2 because the function is incrementing the value.
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Linette
1 year ago
The output is 1.
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