I feel like it should be "22.000000" since the total width is 10, but I can't recall if the leading zeros apply to the whole number or just the integer part.
I've got this! The answer is D. The printf function will convert the integer 22 to a floating-point number and print it with 6 decimal places, padded with zeros to make it 10 characters wide.
Okay, I think I know this one. The format specifier '%010.6f' will print the number with 10 total characters, including 6 decimal places, and pad the left side with zeros.
Hmm, this looks like a formatting question. I'll need to think carefully about the printf format specifier and how it will handle the integer value of 22.
Ah, the age-old question: how many zeros can you fit in front of a number before it becomes a completely different number? The answer is 'as many as you want, as long as you're feeling lucky'.
Hold on, is this a trick question? What if the function is actually supposed to print '22.000000' but the formatting is just really weird? I'll go with B, just to be safe.
Barbra
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