U.S. Independence Day Deal! Unlock 25% OFF Today – Limited-Time Offer - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Zend 200-710 Exam - Topic 2 Question 37 Discussion

Given a PHP value, which sample shows how to convert the value to JSON?
B) $string = Json::encode($value);
A) $string = json_encode($value);
C) $json = new Json($value); $string = $json->__toString();
D) $value = (object) $value; $string = $value->__toJson();

Zend 200-710 Exam - Topic 2 Question 37 Discussion

Actual exam question for Zend's 200-710 exam
Question #: 37
Topic #: 2
[All 200-710 Questions]

Given a PHP value, which sample shows how to convert the value to JSON?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Tiera at Oct 14, 2022, 11:17 AM

Limited Time Offer

25%

Off

Get Premium 200-710 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Rebeca
8 months ago
Surprised that people still confuse these methods!
upvoted 0 times
...
Adelina
8 months ago
I thought D was a thing, but it seems off.
upvoted 0 times
...
Earleen
8 months ago
Wait, are B and C even valid?
upvoted 0 times
...
Ashlyn
8 months ago
Definitely agree, json_encode is the standard.
upvoted 0 times
...
Lezlie
8 months ago
A is the correct way to convert to JSON!
upvoted 0 times
...
Jamey
9 months ago
I have a vague memory of option D, but I don't think PHP has a __toJson() method for objects.
upvoted 0 times
...
Marta
9 months ago
Option C seems off to me; I don't recall using the new Json() syntax in PHP.
upvoted 0 times
...
Carline
9 months ago
I'm not entirely sure, but I feel like Json::encode in option B is related to a framework I studied.
upvoted 0 times
...
Tamar
9 months ago
I think option A looks familiar; I remember using json_encode in my practice questions.
upvoted 0 times
...
Louvenia
9 months ago
Wait, I'm a little confused. How do we determine the number of APs needed? Is it just a simple calculation based on the client count, or are there other factors to consider? I want to make sure I understand this properly before selecting an answer.
upvoted 0 times
...
Daniela
9 months ago
Hmm, I'm not entirely sure about this one. I think I need to double-check the GoldenGate documentation to make sure I fully understand the differences between the available options. I want to make sure I select the right approach for detecting update and delete conflicts.
upvoted 0 times
...
Maxima
9 months ago
This is a tricky one, but I'm pretty sure the answer is A. The other options seem to be describing physical characteristics, not leadership types. I'll mark A and move on.
upvoted 0 times
...
Salena
9 months ago
I feel like I recall something about nodes and decentralization, but I'm struggling to remember exactly how they all fit together.
upvoted 0 times
...
Simona
9 months ago
Aha, I see what they're getting at. If an iRule references an event that doesn't occur, that could cause issues with the client's connection. I'll go with that option.
upvoted 0 times
...
Rickie
1 year ago
I wonder if option D involves turning the value into a Transformer first, and then converting it to JSON. Probably best to keep it simple with json_encode().
upvoted 0 times
Arlene
1 year ago
B) $string = Json::encode($value);
upvoted 0 times
...
Therese
1 year ago
Yes, that's the correct way to convert a PHP value to JSON.
upvoted 0 times
...
Viola
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
...
Trina
1 year ago
If I see 'Json' with a capital 'J', I automatically assume it's not the standard PHP function. json_encode() all the way!
upvoted 0 times
...
Lynda
1 year ago
Converting the value to an object and then calling a custom __toJson() method? That's just weird. json_encode() is the way to go.
upvoted 0 times
Jeannetta
1 year ago
B) $string = Json::encode($value);
upvoted 0 times
...
Delbert
1 year ago
Yeah, json_encode() is the standard way to convert PHP values to JSON.
upvoted 0 times
...
Laurel
1 year ago
B) $string = Json::encode($value);
upvoted 0 times
...
Lili
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
Brynn
1 year ago
Yeah, json_encode() is definitely the way to go.
upvoted 0 times
...
Ashlee
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
...
Natalie
1 year ago
Creating a new Json object and then converting it to a string? That seems overly complicated. I'll stick with the simple json_encode() method.
upvoted 0 times
Louisa
1 year ago
B) $string = Json::encode($value);
upvoted 0 times
...
Wilda
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
Berry
1 year ago
B) $string = Json::encode($value);
upvoted 0 times
...
Angella
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
Kristeen
1 year ago
I agree, json_encode() is much simpler.
upvoted 0 times
...
Simona
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
...
Brice
1 year ago
Option B looks like it might be a custom function, but I'm not familiar with it. I'll go with the built-in json_encode() function.
upvoted 0 times
Whitley
1 year ago
Yeah, json_encode() is a built-in function for converting PHP values to JSON.
upvoted 0 times
...
Clarinda
1 year ago
I agree, json_encode() is the way to go.
upvoted 0 times
...
...
Dylan
1 year ago
The correct answer is A. json_encode() is the standard PHP function to convert a value to JSON.
upvoted 0 times
Adrianna
1 year ago
Yes, that's correct. json_encode() is the way to go.
upvoted 0 times
...
Nichelle
1 year ago
A) $string = json_encode($value);
upvoted 0 times
...
...
Kattie
1 year ago
I'm not sure, but I think B) $string = Json::encode($value); could also be a valid option.
upvoted 0 times
...
Chan
1 year ago
I agree with Tonette, json_encode is the right function to convert PHP value to JSON.
upvoted 0 times
...
Tonette
1 year ago
I think the correct answer is A) $string = json_encode($value);
upvoted 0 times
...

Save Cancel