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Zend 200-710 Exam - Topic 2 Question 37 Discussion

Actual exam question for Zend's 200-710 exam
Question #: 37
Topic #: 2
[All 200-710 Questions]

Given a PHP value, which sample shows how to convert the value to JSON?

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Suggested Answer: B

by Tiera at Oct 14, 2022, 11:17 AM

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Rebeca
6 months ago
Surprised that people still confuse these methods!
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Adelina
6 months ago
I thought D was a thing, but it seems off.
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Earleen
7 months ago
Wait, are B and C even valid?
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Ashlyn
7 months ago
Definitely agree, json_encode is the standard.
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Lezlie
7 months ago
A is the correct way to convert to JSON!
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Jamey
7 months ago
I have a vague memory of option D, but I don't think PHP has a __toJson() method for objects.
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Marta
7 months ago
Option C seems off to me; I don't recall using the new Json() syntax in PHP.
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Carline
7 months ago
I'm not entirely sure, but I feel like Json::encode in option B is related to a framework I studied.
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Tamar
7 months ago
I think option A looks familiar; I remember using json_encode in my practice questions.
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Louvenia
7 months ago
Wait, I'm a little confused. How do we determine the number of APs needed? Is it just a simple calculation based on the client count, or are there other factors to consider? I want to make sure I understand this properly before selecting an answer.
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Daniela
7 months ago
Hmm, I'm not entirely sure about this one. I think I need to double-check the GoldenGate documentation to make sure I fully understand the differences between the available options. I want to make sure I select the right approach for detecting update and delete conflicts.
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Maxima
7 months ago
This is a tricky one, but I'm pretty sure the answer is A. The other options seem to be describing physical characteristics, not leadership types. I'll mark A and move on.
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Salena
7 months ago
I feel like I recall something about nodes and decentralization, but I'm struggling to remember exactly how they all fit together.
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Simona
8 months ago
Aha, I see what they're getting at. If an iRule references an event that doesn't occur, that could cause issues with the client's connection. I'll go with that option.
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Rickie
1 year ago
I wonder if option D involves turning the value into a Transformer first, and then converting it to JSON. Probably best to keep it simple with json_encode().
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Arlene
11 months ago
B) $string = Json::encode($value);
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Therese
11 months ago
Yes, that's the correct way to convert a PHP value to JSON.
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Viola
11 months ago
A) $string = json_encode($value);
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Trina
1 year ago
If I see 'Json' with a capital 'J', I automatically assume it's not the standard PHP function. json_encode() all the way!
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Lynda
1 year ago
Converting the value to an object and then calling a custom __toJson() method? That's just weird. json_encode() is the way to go.
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Jeannetta
11 months ago
B) $string = Json::encode($value);
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Delbert
12 months ago
Yeah, json_encode() is the standard way to convert PHP values to JSON.
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Laurel
12 months ago
B) $string = Json::encode($value);
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Lili
12 months ago
A) $string = json_encode($value);
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Brynn
12 months ago
Yeah, json_encode() is definitely the way to go.
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Ashlee
12 months ago
A) $string = json_encode($value);
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Natalie
1 year ago
Creating a new Json object and then converting it to a string? That seems overly complicated. I'll stick with the simple json_encode() method.
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Louisa
11 months ago
B) $string = Json::encode($value);
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Wilda
11 months ago
A) $string = json_encode($value);
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Berry
11 months ago
B) $string = Json::encode($value);
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Angella
11 months ago
A) $string = json_encode($value);
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Kristeen
12 months ago
I agree, json_encode() is much simpler.
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Simona
12 months ago
A) $string = json_encode($value);
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Brice
1 year ago
Option B looks like it might be a custom function, but I'm not familiar with it. I'll go with the built-in json_encode() function.
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Whitley
1 year ago
Yeah, json_encode() is a built-in function for converting PHP values to JSON.
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Clarinda
1 year ago
I agree, json_encode() is the way to go.
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Dylan
1 year ago
The correct answer is A. json_encode() is the standard PHP function to convert a value to JSON.
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Adrianna
11 months ago
Yes, that's correct. json_encode() is the way to go.
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Nichelle
1 year ago
A) $string = json_encode($value);
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Kattie
1 year ago
I'm not sure, but I think B) $string = Json::encode($value); could also be a valid option.
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Chan
1 year ago
I agree with Tonette, json_encode is the right function to convert PHP value to JSON.
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Tonette
1 year ago
I think the correct answer is A) $string = json_encode($value);
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