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UiPath-ARDv1 Exam - Topic 5 Question 99 Discussion

Actual exam question for UiPath's UiPath-ARDv1 exam
Question #: 99
Topic #: 5
[All UiPath-ARDv1 Questions]

What will be the value of isEven variable at the breakpoint, once the robot runs in Debug mode?

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Suggested Answer: C

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Delisa
3 months ago
I agree with False, but I'm not 100% sure!
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Linwood
3 months ago
I’m leaning towards null, seems plausible.
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Alison
3 months ago
Wait, could it actually be empty?
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Lorean
4 months ago
Definitely False, no doubt about it.
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Darci
4 months ago
I think it will be True.
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Golda
4 months ago
If I recall correctly, if the input number is even, isEven should be True, but I can't remember if there's a specific condition that could make it False.
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Ryann
4 months ago
I'm a bit confused about whether the variable can be empty or null at the breakpoint. I feel like I need to double-check the initialization part.
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Lashaunda
4 months ago
I remember a similar question where we had to determine if a number was odd or even, and I think it was based on the modulus operator.
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Christiane
5 months ago
I think the isEven variable should be True if the number is even, but I'm not entirely sure what the input is in this case.
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Vallie
5 months ago
Hmm, I'm not sure about this one. I'll need to review the logic carefully and make sure I understand how the isEven variable is being set.
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Cherrie
5 months ago
I'm pretty confident I know the answer to this one. The key is to pay close attention to the flow of execution and how the If-Else statement is being evaluated.
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Adolph
5 months ago
Wait, I'm a bit confused. The options include "empty" and "null" - does that mean the variable could be something other than a boolean value?
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King
5 months ago
Okay, I think I've got this. The image shows a simple If-Else statement, so the value of isEven should be either True or False depending on the input.
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Lucina
5 months ago
Hmm, this looks like a tricky one. I'll need to carefully step through the code in Debug mode to see how the isEven variable is being set.
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Jeffrey
9 months ago
I wonder if the robot has a sense of humor and is just messing with us. Maybe 'isEven' is secretly 'isFunny' and the answer is C) empty, just to keep us on our toes!
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Bette
8 months ago
Maybe it's C) empty, just to confuse us!
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Bette
8 months ago
I believe the answer is B) True, robots follow strict rules.
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Bette
8 months ago
I think it could be A) False, robots tend to be very logical.
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Kimberlie
10 months ago
Wait, is this a trick question? I mean, the image shows 'true', but what if the robot has a bug and it's actually false? I better double-check my work.
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Junita
8 months ago
User 3: Maybe we should double-check just to be sure.
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Scarlet
8 months ago
User 2: I agree, it looks like the value will be True.
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Ashton
9 months ago
User 1: I think it will be True.
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Valentine
11 months ago
Woohoo, this is a no-brainer! The robot is clearly setting 'isEven' to 'true', so the answer has to be B) True. I'm gonna ace this exam!
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Rachael
9 months ago
Yeah, it's a no-brainer, the answer has to be B) True.
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Ceola
9 months ago
I think you're right, the robot is definitely setting 'isEven' to 'true'.
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Emmett
11 months ago
Hmm, I'm not sure about this one. The variable name 'isEven' makes me think it should be a boolean, but C) empty or D) null could also be possible. I'll have to think this through carefully.
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Dorothy
10 months ago
I'm not sure either, but I think it might be D) null.
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Talia
10 months ago
I'm leaning towards C) empty.
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Jaleesa
10 months ago
I believe it will be A) False.
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Otis
10 months ago
I think the value will be B) True.
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Wava
11 months ago
I'm not sure, but I think it could be null if the variable is not initialized properly.
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Ivette
11 months ago
I think the answer is B) True. The image clearly shows that the 'isEven' variable is assigned the value 'true' at the breakpoint.
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Pamella
11 months ago
I agree with Nenita, the value will be False as the robot runs in Debug mode.
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Nenita
11 months ago
I think the value will be False because isEven variable will not be true at the breakpoint.
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