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Snowflake SOL-C01 Exam - Topic 4 Question 12 Discussion

Posted by Reynalda on May 29, 2026 at 03:08 AM

What is the purpose of the PARSE_JSON function in Snowflake?

Suggested Answer: D

The PARSE_JSON() function ingests a string containing JSON text and converts it into Snowflake'sVARIANTdata type, enabling the JSON to be queried, navigated, and transformed using SQL. Snowflake does not store JSON in its raw textual representation; instead, VARIANT allows Snowflake to apply optimized parsing, indexing, and querying operations against semi-structured content. This function is particularly useful when JSON arrives inline (e.g., supplied directly within SQL statements or loaded from CSV files containing JSON strings). PARSE_JSON does not perform data loading from stages---that is handled through COPY INTO---nor does it convert JSON into XML. Once JSON is converted to VARIANT, Snowflake allows access to nested structures using dot notation, bracket notation, and functions like FLATTEN(). Thus, the function serves as a bridge between raw JSON strings and Snowflake's relational and analytical capabilities.

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16 comments · newest first
AL
Alisha 25 days ago
I’m with you all, D is the clear answer.
BE
Beth 1 month ago
But without parsing, how do we analyze? D is the best choice!
GE
Georgene 1 month ago
I lean towards C. Loading is crucial for workflows.
SH
Sherita 1 month ago
Definitely D! It helps in data analysis.
CE
Cecil 2 months ago
I feel A could be right too, but parsing is more relevant.
JA
Jacinta 2 months ago
Agreed, D makes sense. Relational format is important.
CA
Catrice 2 months ago
I think it's D. Parsing is key!
RO
Royal 2 months ago
I disagree, it’s not about XML at all!
VA
Valentine 2 months ago
I thought it was for loading data, but it's not.
LO
Lourdes 2 months ago
Wait, it doesn't store JSON? That's surprising!
MA
Marsha 3 months ago
Definitely D, no doubt about it.
ES
Essie 3 months ago
It's all about parsing JSON into tables!
DA
Dacia 3 months ago
I vaguely recall that PARSE_JSON is not for converting to XML or loading from stages, so I guess it must be about parsing it, but I can't remember the details.
CH
Chauncey 3 months ago
I’m a bit confused; I thought PARSE_JSON was just for storing JSON data. Is it really about parsing it into a table format?
KA
Kanisha 3 months ago
I remember practicing a question similar to this, and I think it was about how Snowflake handles JSON data. I feel like option D makes the most sense.
KR
Kristeen 3 months ago
I think the PARSE_JSON function is about converting JSON data into a format that can be used in tables, but I'm not entirely sure if it's specifically for relational tables.
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