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Snowflake SOL-C01 Exam - Topic 4 Question 12 Discussion

What is the purpose of the PARSE_JSON function in Snowflake?
D) Parsing JSON data into relational table format
A) Storing JSON data in its PARSE format
B) Converting JSON data to XML format
C) Loading JSON data from external stages

Snowflake SOL-C01 Exam - Topic 4 Question 12 Discussion

Actual exam question for Snowflake's SOL-C01 exam
Question #: 12
Topic #: 4
[All SOL-C01 Questions]

What is the purpose of the PARSE_JSON function in Snowflake?

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Suggested Answer: D

The PARSE_JSON() function ingests a string containing JSON text and converts it into Snowflake'sVARIANTdata type, enabling the JSON to be queried, navigated, and transformed using SQL. Snowflake does not store JSON in its raw textual representation; instead, VARIANT allows Snowflake to apply optimized parsing, indexing, and querying operations against semi-structured content. This function is particularly useful when JSON arrives inline (e.g., supplied directly within SQL statements or loaded from CSV files containing JSON strings). PARSE_JSON does not perform data loading from stages---that is handled through COPY INTO---nor does it convert JSON into XML. Once JSON is converted to VARIANT, Snowflake allows access to nested structures using dot notation, bracket notation, and functions like FLATTEN(). Thus, the function serves as a bridge between raw JSON strings and Snowflake's relational and analytical capabilities.

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Chauncey
2 days ago
I’m a bit confused; I thought PARSE_JSON was just for storing JSON data. Is it really about parsing it into a table format?
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Kanisha
7 days ago
I remember practicing a question similar to this, and I think it was about how Snowflake handles JSON data. I feel like option D makes the most sense.
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Kristeen
12 days ago
I think the PARSE_JSON function is about converting JSON data into a format that can be used in tables, but I'm not entirely sure if it's specifically for relational tables.
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