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Refer to the exhibit:
The box plot was used to analyze daily sales data following three different ad campaigns.
The business analyst concludes that one of the assumptions of ANOVA was violated.
Which assumption has been violated and why?
Suggested Answer: D
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32 comments · newest first
CA
Carol
10 months ago
Prob > F < .0001 is a big red flag!
CL
Clay
10 months ago
Totally agree, the interquartile ranges are all over the place!
JA
Jade
11 months ago
Wait, how can we be sure it's normality?
OW
Owen
11 months ago
Definitely constant variance being violated, not normality.
KR
Kristeen
11 months ago
Looks like normality is the issue here.
JU
Julieta
11 months ago
I feel like the answer is D, constant variance, because of those different interquartile ranges. We practiced a similar question on this!
JI
Jina
12 months ago
I’m leaning towards normality being the issue, but I can't recall if Prob > F being low directly indicates that.
RO
Rodolfo
12 months ago
I think it might be constant variance since the interquartile ranges look different for the ad campaigns. That sounds familiar from our practice questions.
JO
Joaquin
12 months ago
I remember we discussed ANOVA assumptions in class, but I'm not sure which one is violated here.
PA
Paul
1 year ago
Based on the box plot, I can see the data is not symmetrical, so the normality assumption has likely been violated. The varying interquartile ranges across the ad campaigns also point to an issue with the constant variance assumption.
MA
Martina
1 year ago
Okay, let me think this through. The box plot indicates the data is not normally distributed, so that's probably the assumption that's been violated. The different interquartile ranges also suggest the constant variance assumption may be an issue.
VE
Venita
1 year ago
The question mentions that one of the ANOVA assumptions was violated, so I need to think about which one. The box plot shows the data is skewed, so the normality assumption seems like the most likely culprit here.
OD
Odelia
1 year ago
Hmm, the box plot shows the data is not normally distributed, so I think the normality assumption has been violated. The different interquartile ranges across the ad campaigns also suggest the constant variance assumption may not hold.
SH
Shad
1 year ago
I see, so it's likely that normality assumption is violated in this case.
BO
Bonita
1 year ago
Constant variance? Normality? These statistical terms sound like they're from a different planet! I'll just go with option D and hope for the best.
LI
Linn
1 year ago
That makes sense, let's go with option D then.
LI
Lindsey
1 year ago
I agree, the interquartile ranges are different in different ad campaigns.
DE
Delila
1 year ago
I think option D is the best choice.
RA
Raymon
1 year ago
That could also be a factor, but the probability value is a stronger indicator.
DO
Dortha
1 year ago
But what about the interquartile ranges being different?
SH
Shad
1 year ago
I agree with Raymon, the Prob > F is less than .0001.
JO
Johana
1 year ago
The Prob > F being less than 0.0001 is a dead giveaway that the normality assumption has been violated. Option A is the way to go, my friends.
AS
Asuncion
1 year ago
Yes, option A is the correct choice in this case.
JE
Jettie
1 year ago
I agree, the low Prob > F value indicates a violation of normality assumption.
RA
Raymon
1 year ago
I think the assumption of normality has been violated.
MI
Mitzie
1 year ago
Haha, these ANOVA assumptions are like a game of 'guess the right answer'! I'm going with option D, constant variance, because the box plots don't look very consistent across the campaigns.
BU
Bulah
1 year ago
The interquartile ranges are different in the box plots, so I think the assumption of constant variance has been violated. Option D seems to be the correct answer here.
HI
Hildegarde
1 year ago
Yes, that's why option D is the correct answer.
VE
Vesta
1 year ago
I agree, the different interquartile ranges indicate a violation of constant variance assumption.
JU
Julene
1 year ago
The box plot clearly shows the difference in interquartile ranges, making constant variance assumption invalid.
LE
Leonor
1 year ago
Yes, that's why option D is the correct answer.
LE
Leatha
1 year ago
I agree, the interquartile ranges being different indicate a violation of constant variance.