Salesforce Exam OmniStudio Developer Topic 1 Question 86 Discussion

Actual exam question for Salesforce's OmniStudio Developer exam

Question #: 86
Topic #: 1

A developer creates a FlexCard with five state elements. For of the states have a condition. To test the FlexCard, the developer previews it using sample data that causes two of the states to have true conditions.

In this scenario, how will the developer know which state will display?

AThe first state with true conditions sequence closest to the top of the FlexCard canvas will display.

BThe first state with true nested condition, regardless of sequence in the FlexCard canvas, will display

CThe state sequenced first in the FlexCard canvas will display.

DThe first state with a true AND condition, regardless of sequence in the FlexCard canvas, will display.

Show Suggested Answer

Suggested Answer: D

by Muriel at Mar 08, 2025, 03:56 AM

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Brigette

1 months ago

Wait, is this a trick question? I bet the real answer is that the FlexCard will display a random state just to confuse the developer. That's the kind of thing that would happen to me.

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Gayla

11 days ago

B) The first state with true nested condition, regardless of sequence in the FlexCard canvas, will display.

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Cassie

28 days ago

No way, that can't be right. It must be a trick question.

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Kristin

1 months ago

A) The first state with true conditions sequence closest to the top of the FlexCard canvas will display.

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Ilene

2 months ago

D is the answer, obviously. The first state with a true AND condition, regardless of sequence in the FlexCard canvas, will display. Duh, it's the most specific condition.

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Filiberto

12 days ago

Actually, D is the answer. The first state with a true AND condition, regardless of sequence in the FlexCard canvas, will display.

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Alida

28 days ago

No, I believe it's B. The first state with true nested condition, regardless of sequence in the FlexCard canvas, will display.

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Omega

1 months ago

I think the answer is A. The first state with true conditions sequence closest to the top of the FlexCard canvas will display.

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Shantay

2 months ago

I'm going with B. The first state with true nested condition, regardless of sequence in the FlexCard canvas, will display. That's the most logical choice in my opinion.

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Markus

2 months ago

I'm pretty sure the answer is C. The state sequenced first in the FlexCard canvas will display, regardless of the conditions. That's how I've always seen it work.

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Mona

12 days ago

I think it might be D. The first state with a true AND condition will display.

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Pearline

13 days ago

I'm pretty sure it's C. The state sequenced first in the FlexCard canvas will display.

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Tegan

14 days ago

No, I believe it's B. The first state with true nested condition will display.

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Willow

22 days ago

I think it's A. The first state with true conditions closest to the top will display.

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Venita

2 months ago

But what if the conditions are nested? Wouldn't that affect the display?

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Leatha

2 months ago

The correct answer is A. The first state with true conditions sequence closest to the top of the FlexCard canvas will display. This makes sense since the FlexCard will render the state elements in the order they are defined.

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