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Salesforce Exam Javascript Developer I Topic 9 Question 64 Discussion

Actual exam question for Salesforce's Javascript Developer I exam
Question #: 64
Topic #: 9
[All Javascript Developer I Questions]

Given the following code:

Counter = 0;

const logCounter = () => {

console.log(counter);

);

logCounter();

setTimeout(logCOunter, 1100);

setInterval(() => {

Counter++

logCounter();

}, 1000);

What is logged by the first four log statements?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Cordelia at Jul 30, 2023, 12:25 AM

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Kami
9 days ago
I'm going with D) 0 1 2 2. The setInterval call increments Counter and logs the new value, but the last log statement should be 2 since the interval is 1 second and the setTimeout is 1.1 seconds.
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Michel
18 days ago
That's an interesting point, Matthew. I can see how that could be the case. Let's see what others think.
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Pura
21 days ago
I think the answer is B) 0 1 2 3. The code sets the Counter variable to 0, and then the first logCounter() call logs 0. The setTimeout call logs 0 after 1.1 seconds, and the setInterval call increments Counter and logs the new value every 1 second, so the output should be 0 1 2 3.
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Tabetha
3 hours ago
Yes, that's correct. The first log statement logs 0.
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Torie
3 days ago
I think the answer is B) 0 1 2 3.
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Matthew
22 days ago
I disagree, I believe the answer is C) 0 1 1 2 because the logCounter function is called twice before the counter is incremented.
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Michel
1 months ago
I think the answer is B) 0 1 2 3 because the counter starts at 0 and then increments by 1 each time it is logged.
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