Independence Day Deal! Unlock 25% OFF Today – Limited-Time Offer - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Salesforce Exam Javascript Developer I Topic 9 Question 64 Discussion

Actual exam question for Salesforce's Javascript Developer I exam
Question #: 64
Topic #: 9
[All Javascript Developer I Questions]

Given the following code:

Counter = 0;

const logCounter = () => {

console.log(counter);

);

logCounter();

setTimeout(logCOunter, 1100);

setInterval(() => {

Counter++

logCounter();

}, 1000);

What is logged by the first four log statements?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Cordelia at Jul 30, 2023, 12:25 AM

Limited Time Offer

25%

Off

Get Premium Javascript Developer I Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel
Edwin
1 months ago
Someone should tell the exam writers that their code needs a little more 'set' and a little less 'time-out'.
upvoted 0 times
Stephaine
19 hours ago
A) 0 0 1 2
upvoted 0 times
...
...
Mila
1 months ago
I bet the exam writers were chuckling to themselves when they came up with this one. 'Let's see if they can keep up with our asynchronous antics!'
upvoted 0 times
...
Dante
1 months ago
This question is a real head-scratcher! I'm going to go with B) 0 1 2 3 because it just makes the most sense to me. But who knows, maybe the exam writers are trying to trick us with this one.
upvoted 0 times
...
Galen
1 months ago
I'm confused. Shouldn't the answer be C) 0 1 1 2? The first logCounter() call logs 0, the setTimeout call logs 1, and the setInterval call increments Counter and logs the new value, but the last log statement should be 2, not 3.
upvoted 0 times
Brande
10 days ago
B) 0 1 2 3
upvoted 0 times
...
Leonida
14 days ago
No, that's not correct. The first logCounter() call logs 0, the setTimeout call logs 0 again, and the setInterval call increments Counter and logs the new value.
upvoted 0 times
...
Patria
24 days ago
A) 0 0 1 2
upvoted 0 times
...
...
Kami
2 months ago
I'm going with D) 0 1 2 2. The setInterval call increments Counter and logs the new value, but the last log statement should be 2 since the interval is 1 second and the setTimeout is 1.1 seconds.
upvoted 0 times
Mona
5 days ago
I think it's A) 0 0 1 2. The first log statement logs the initial value of Counter, which is 0. Then the setInterval increments Counter and logs it, so it goes 0 0 1 2.
upvoted 0 times
...
Truman
10 days ago
I agree with D) 0 1 2 2. The setTimeout call logs the Counter after the interval.
upvoted 0 times
...
Thora
25 days ago
I'm going with D) 0 1 2 2. The setInterval call increments Counter and logs the new value.
upvoted 0 times
...
Dewitt
1 months ago
I believe it's B) 0 1 2 3. The Counter is incremented before it is logged.
upvoted 0 times
...
Golda
1 months ago
I think it's A) 0 0 1 2. The Counter is logged before it is incremented.
upvoted 0 times
...
...
Michel
2 months ago
That's an interesting point, Matthew. I can see how that could be the case. Let's see what others think.
upvoted 0 times
...
Pura
2 months ago
I think the answer is B) 0 1 2 3. The code sets the Counter variable to 0, and then the first logCounter() call logs 0. The setTimeout call logs 0 after 1.1 seconds, and the setInterval call increments Counter and logs the new value every 1 second, so the output should be 0 1 2 3.
upvoted 0 times
Margret
1 months ago
Finally, the setInterval call increments Counter and logs the new value every 1 second.
upvoted 0 times
...
Alex
1 months ago
Then the setTimeout call logs 0 after 1.1 seconds.
upvoted 0 times
...
Tabetha
2 months ago
Yes, that's correct. The first log statement logs 0.
upvoted 0 times
...
Torie
2 months ago
I think the answer is B) 0 1 2 3.
upvoted 0 times
...
...
Matthew
2 months ago
I disagree, I believe the answer is C) 0 1 1 2 because the logCounter function is called twice before the counter is incremented.
upvoted 0 times
...
Michel
3 months ago
I think the answer is B) 0 1 2 3 because the counter starts at 0 and then increments by 1 each time it is logged.
upvoted 0 times
...

Save Cancel