Salesforce Exam Javascript Developer I Topic 5 Question 68 Discussion

Actual exam question for Salesforce's Javascript Developer I exam

Question #: 68
Topic #: 5

[All Javascript Developer I Questions]

Refer to code below:

console.log(0);

setTimeout(() => (

console.log(1);

});

console.log(2);

setTimeout(() => {

console.log(3);

), 0);

console.log(4);

In which sequence will the numbers be logged?

A01234

B02431

C02413

D13024

Show Suggested Answer

Suggested Answer: B

by Kirk at Oct 19, 2023, 02:37 PM

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Miesha

1 months ago

Okay, let's do this! I'm feeling confident with B) 02431. Those setTimeout's with a 0 millisecond delay always get executed after the current synchronous code. Gotta love JavaScript's quirks, am I right?

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Brendan

2 days ago

JavaScript can be tricky sometimes, but it's always interesting to see how it works.

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Gwenn

30 days ago

Yeah, that's correct. The setTimeout with 0 millisecond delay will be executed after the synchronous code.

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Gary

1 months ago

I think you're right! The numbers will be logged in the sequence 02431.

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Callie

2 months ago

Haha, this one's a real brain-teaser! I'm gonna go with C) 02413 just to be different. Who knows, maybe the exam folks are trying to catch us out with a trick question.

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Queenie

2 months ago

Hmm, let's see... If I remember my JavaScript fundamentals, the console.log's will execute in the order they're written, and the setTimeout's will get added to the task queue. So the answer has to be B) 02431. I hope I'm right!

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Alton

5 days ago

That makes sense, the setTimeout functions have a delay of 0 milliseconds, so they will be executed after the initial console.log statements. B) 02431 seems correct.

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William

15 days ago

Yes, that's correct. The numbers will be logged in the order 0, 2, 4, 3, 1. Good job!

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Myong

16 days ago

I think you're right, the setTimeout functions will be added to the task queue and logged after the initial console.log statements.

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Filiberto

19 days ago

Yes, that's correct! The setTimeout functions will be executed after the initial console.log statements, following the order they were added to the task queue. So it's definitely B) 02431.

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Mila

20 days ago

I think you're right, the setTimeout functions will be added to the task queue and executed after the console.log statements. So it should be B) 02431.

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Rodrigo

1 months ago

I think you're right, the setTimeout functions will be added to the task queue and executed after the initial console.log statements. So it should be B) 02431.

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Doyle

2 months ago

Hmm, that's an interesting point. I see your rationale. Let's wait for others to share their opinions.

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Beth

2 months ago

Ah, the classic event loop conundrum! I'm pretty sure the correct answer is B) 02431. Those setTimeout's can be tricky, but I think I've got the hang of it now.

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