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Salesforce Exam Salesforce Certified JavaScript Developer (JS-Dev-101) Topic 4 Question 85 Discussion

Actual exam question for Salesforce's Salesforce Certified JavaScript Developer (JS-Dev-101) exam
Question #: 85
Topic #: 4
[All Salesforce Certified JavaScript Developer (JS-Dev-101) Questions]

Refer to code below:

function Person() {

this.firstName = 'John';

}

Person.prototype ={

Job: x => 'Developer'

};

const myFather = new Person();

const result=myFather.firstName + ' ' + myFather.job();

What is the value of the result after line 10 executes?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Buddy at Jul 17, 2024, 07:54 PM

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Alberto
5 days ago
The method is named 'Job' not 'job'.
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Catalina
11 days ago
I’m leaning towards option A, but I’m confused about the prototype syntax. I thought methods defined in the prototype should be accessible.
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Claribel
16 days ago
I practiced a similar question, and I feel like the result might be "John undefined" because `job` is not a method on `myFather`.
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Michal
22 days ago
I'm not entirely sure, but I remember something about how JavaScript handles prototypes. Could it be that it results in an error since `job` isn't defined on the instance?
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Armanda
28 days ago
I think the function is trying to access `myFather.job()`, but it should be `myFather.Job()` since it's defined in the prototype.
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Kenneth
28 days ago
Ah, I see the issue now. The `Job` property is defined using an arrow function, which means it's not a method that can be called. The correct answer is D.
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Frederic
28 days ago
I think I've got it! The `Job` property on the prototype is defined using an arrow function, so we can't call it as a method. The correct answer must be D, "John Developer".
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Pearlene
28 days ago
I'm a bit confused here. The question says to refer to the code, but the code doesn't have a `job()` method defined. I'll need to think this through more carefully.
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Deonna
29 days ago
Hmm, this looks tricky. I'll need to carefully read through the code and think about how the `Person` object and its prototype are set up.
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Carmen
1 months ago
Okay, let me break this down step-by-step. The `Person` constructor sets the `firstName` property, and the prototype has a `Job` property that's an arrow function. So the issue is how to access that `Job` property.
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German
1 months ago
Okay, I think I've got this. If the packet is already associated with an existing session, it should go through the fast path without needing session establishment. The key is figuring out how the content inspection works in that scenario.
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Malika
1 months ago
I think maximizing response R means we should probably be looking at the highest grades, so maybe A+ and B+? But I'm not entirely sure.
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Jordan
6 months ago
Wait, is this a trick question? I'm going to go with option D, but I'm secretly hoping it's a joke and the real answer is 'John, the Developer'.
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Carlee
5 months ago
Yeah, it makes sense that the result would be 'John Developer'.
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Azalee
5 months ago
I agree, it should be 'John Developer'.
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Rodney
5 months ago
I think it's option D, 'John Developer'.
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Clare
6 months ago
Haha, this code is a bit of a mess, isn't it? I'm going to have to go with option D though - 'John Developer'. It's the only one that makes sense to me.
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Garry
5 months ago
Definitely, option D is the only one that fits with the code logic.
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Justine
5 months ago
Yeah, I agree. 'John Developer' makes the most sense given the code provided.
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Jill
5 months ago
Definitely, option D is the only one that fits with the code logic.
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Valentin
6 months ago
I think you're right, option D does seem to be the correct answer.
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Tequila
6 months ago
Yeah, I agree. 'John Developer' makes the most sense given the code provided.
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Rose
6 months ago
I think you're right, option D does seem to be the correct answer.
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Dalene
6 months ago
This is a tricky one! I'm going to have to agree with Enola - that arrow function on the prototype is going to cause some issues. I'll go with option A as well.
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Enola
7 months ago
Wait, why is the 'Job' property declared with an arrow function? That's not going to work the way we expect. I think I'll have to go with option A - 'Error: myFather.job is not a function'.
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Stephanie
5 months ago
Looks like option A is the correct choice.
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Dalene
5 months ago
So 'myFather.job' is not a function because of that.
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Jerry
5 months ago
Yeah, arrow functions don't bind 'this' like regular functions do.
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Lindsey
6 months ago
I think you're right, the arrow function syntax is causing an issue here.
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Shelia
7 months ago
Hmm, the problem seems to be that we're trying to access the 'job' property directly instead of using the 'Job' method on the prototype. I'll go with option D - 'John Developer'.
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Mike
6 months ago
Yes, you're right. We need to use the 'Job' method on the prototype to access the value.
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Gracia
6 months ago
So, the correct answer is D) John Developer.
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Antonio
6 months ago
Yeah, the 'Job' method on the prototype should be used.
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Elenor
6 months ago
I agree, it should be 'John Developer'.
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Kristel
6 months ago
I think the value of result is 'John Developer'.
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Eun
6 months ago
I think the correct answer is D) John Developer.
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Gracia
7 months ago
But the code defines the Job property on the Person prototype, so it should be D) John Developer.
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Patti
7 months ago
I disagree, I believe it's A) Error: myFather.job is not a function.
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Gracia
7 months ago
I think the value of the result is D) John Developer.
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