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Salesforce Exam Javascript Developer I Topic 3 Question 89 Discussion

Actual exam question for Salesforce's Javascript Developer I exam
Question #: 89
Topic #: 3
[All Javascript Developer I Questions]

Given the code below:

Setcurrent URL ();

console.log('The current URL is: ' +url );

functionsetCurrentUrl() {

Url = window.location.href:

What happens when the code executes?

Show Suggested Answer Hide Answer
Suggested Answer: B

by Dean at Sep 19, 2024, 03:42 PM

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Felicia
28 days ago
Hey, did anyone else notice the typo in the function name? It's `Setcurrent URL ()` instead of `setCurrentUrl()`. No wonder this code is giving us headaches!
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Edelmira
2 days ago
I think the correct function name should be `setCurrentUrl()`. That would fix the problem.
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Felix
4 days ago
Oh, I see what you mean. That typo could definitely cause some issues.
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Bok
1 months ago
I'm just gonna close my eyes and point to an answer. Hey, what do you know? I landed on option C. Global scope, but still throws an error. Must be a bug in the code or something.
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Ryan
4 days ago
Yeah, it's weird that it's a global variable but still throws an error. Must be a mistake in the code.
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Janessa
14 days ago
I think you're right, it seems like the url variable is global but there's an error on line 02.
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Cassandra
2 months ago
Woah, hold up! What if the `setCurrentUrl()` function is actually setting the `url` variable to `window.location.href`, which could be different from the global `url` variable? In that case, option D might be the correct answer.
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Angelo
4 days ago
User 3: I agree, the function could be changing the url variable locally.
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Teddy
11 days ago
User 2: Yeah, that could be a possibility. It's important to consider the function's behavior.
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Theron
30 days ago
User 1: I think option D might be correct if the function is setting the url variable.
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Buck
2 months ago
I'm going with option B. The `url` variable is global, so `console.log('The current URL is: ' + url)` should work just fine.
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Thomasena
2 months ago
But doesn't the function setCurrentUrl() define the url variable locally?
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Catina
2 months ago
Hmm, this looks like a classic scope issue. I'm guessing the variable `url` is declared outside the `setCurrentUrl()` function, so it should have global scope. Let's see what the rest of the candidates think.
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Ashlyn
1 months ago
B) The url variable has global scope and line 02 executes correctly.
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Lemuel
1 months ago
A) The url variable has local scope and line 02 throws an error.
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Lauran
2 months ago
I believe it's C.
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Thomasena
2 months ago
I think the answer is B.
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