Python Institute PCPP-32-101 Exam - Topic 8 Question 34 Discussion

Actual exam question for Python Institute's PCPP-32-101 exam

Question #: 34
Topic #: 8

[All PCPP-32-101 Questions]

A socket object is usually created by which one of the following invocations?

Asocket. socket (socket_domain, socket_type)

Bsocket = socket. socket (socket_number)

Csocket = socket. socket (socket_domain, socket_type, server_address)

Dsocket = socket.socket(server address)

Show Suggested Answer

Suggested Answer: D

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by Zita at Sep 13, 2024, 02:04 AM

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Levi

3 months ago

I’m not sure about C, that seems too complicated for just creating a socket.

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Lenora

3 months ago

A is correct, no doubt about it!

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Kaycee

4 months ago

Wait, can you really create a socket without specifying the address? Sounds odd.

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Raymon

4 months ago

I thought it was B at first, but A makes more sense.

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Terry

4 months ago

It's definitely A, that's the standard way to create a socket.

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Harrison

4 months ago

I feel like I’ve seen something similar in our notes, but I can’t recall if it was A or C that was emphasized more.

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Na

4 months ago

I’m a bit confused; I thought you needed to include the server address too, like in option C.

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Van

5 months ago

I remember practicing a question like this, and I think it was definitely about specifying both domain and type, so A seems right.

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Maybelle

5 months ago

I think the correct invocation is A, but I’m not entirely sure about the parameters.

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Stevie

5 months ago

I'm a little confused by the wording of the options. Do we need to include the server address when creating the socket? I'm not sure if that's required or just an optional parameter. I'll have to double-check my notes to be sure.

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Starr

5 months ago

Okay, let me walk through this step-by-step. The question is asking about how to create a socket object, and the options mention different parameters. I think A is the correct answer, as it matches the typical socket.socket() invocation that we've used in our examples.

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Detra

5 months ago

Hmm, I'm a bit unsure about this one. I know we covered sockets in class, but I can't quite remember the exact syntax for creating a new socket object. I'll have to think this through carefully.

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Roselle

5 months ago

This looks like a straightforward socket question. I'm pretty confident that the answer is A - socket.socket(socket_domain, socket_type).

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Valentin

5 months ago

Hmm, the wording on this question is a bit tricky. I want to make sure I don't miss any important nuances about the connection modes and configuration requirements.

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Penney

10 months ago

Option A, because creating sockets is as easy as A-B-C... D is for dummies.

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Zona

8 months ago

Yeah, D is definitely not the right choice.

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Jutta

9 months ago

I agree, creating sockets is as easy as A-B-C.

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Cecilia

9 months ago

I think A is the correct option.

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Sommer

10 months ago

I'm going with B. It's simple and straight to the point, just like my coding style.

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Sanda

8 months ago

User 3: B sounds good to me, simple is always better.

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Adell

8 months ago

User 2: I'm going with C, it seems more comprehensive.

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Novella

9 months ago

User 1: I think A is the correct answer.

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Percy

10 months ago

D is clearly the wrong answer. You can't create a socket by just passing the server address. That doesn't make any sense.

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Jamal

10 months ago

I think C is the correct answer. The socket.socket() function takes three arguments: the socket domain, socket type, and the server address.

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Aleisha

9 months ago

Actually, B) socket = socket. socket (socket_number) is the correct answer.

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Casie

9 months ago

I'm pretty sure it's D) socket = socket.socket(server address).

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Nan

9 months ago

No, I think it's A) socket. socket (socket_domain, socket_type).

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Annamae

10 months ago

I agree, C is the correct answer.

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Carline

11 months ago

Option A looks right to me. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Caprice

9 months ago

Great, thanks for clarifying that!

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Xuan

9 months ago

So, the correct invocation is socket.socket(socket_domain, socket_type).

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Jess

10 months ago

User 2: Yes, that's correct. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Jodi

10 months ago

Yes, I agree. The socket module's socket() function takes the domain and type as arguments.

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Margot

10 months ago

I think option A is correct.

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Maxima

10 months ago

User 1: I think the answer is A) socket. socket (socket_domain, socket_type)

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Katie

11 months ago

I'm not sure, but I think D) socket = socket.socket(server address) doesn't seem right

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Miriam

11 months ago

I believe it's C) socket = socket.socket(socket_domain, socket_type, server_address)

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Ludivina

11 months ago

I think the answer is A) socket.socket(socket_domain, socket_type)

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