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Python Institute PCPP-32-101 Exam - Topic 8 Question 34 Discussion

Actual exam question for Python Institute's PCPP-32-101 exam

Question #: 34
Topic #: 8

[All PCPP-32-101 Questions]

A socket object is usually created by which one of the following invocations?

Asocket. socket (socket_domain, socket_type)

Bsocket = socket. socket (socket_number)

Csocket = socket. socket (socket_domain, socket_type, server_address)

Dsocket = socket.socket(server address)

Show Suggested Answer

Suggested Answer: D

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by Zita at Sep 13, 2024, 02:04 AM

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Levi

8 months ago

I’m not sure about C, that seems too complicated for just creating a socket.

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Lenora

8 months ago

A is correct, no doubt about it!

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Kaycee

8 months ago

Wait, can you really create a socket without specifying the address? Sounds odd.

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Raymon

9 months ago

I thought it was B at first, but A makes more sense.

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Terry

9 months ago

It's definitely A, that's the standard way to create a socket.

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Harrison

9 months ago

I feel like I’ve seen something similar in our notes, but I can’t recall if it was A or C that was emphasized more.

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Na

9 months ago

I’m a bit confused; I thought you needed to include the server address too, like in option C.

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Van

9 months ago

I remember practicing a question like this, and I think it was definitely about specifying both domain and type, so A seems right.

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Maybelle

10 months ago

I think the correct invocation is A, but I’m not entirely sure about the parameters.

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Stevie

10 months ago

I'm a little confused by the wording of the options. Do we need to include the server address when creating the socket? I'm not sure if that's required or just an optional parameter. I'll have to double-check my notes to be sure.

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Starr

10 months ago

Okay, let me walk through this step-by-step. The question is asking about how to create a socket object, and the options mention different parameters. I think A is the correct answer, as it matches the typical socket.socket() invocation that we've used in our examples.

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Detra

10 months ago

Hmm, I'm a bit unsure about this one. I know we covered sockets in class, but I can't quite remember the exact syntax for creating a new socket object. I'll have to think this through carefully.

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Roselle

10 months ago

This looks like a straightforward socket question. I'm pretty confident that the answer is A - socket.socket(socket_domain, socket_type).

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Valentin

10 months ago

Hmm, the wording on this question is a bit tricky. I want to make sure I don't miss any important nuances about the connection modes and configuration requirements.

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Penney

1 year ago

Option A, because creating sockets is as easy as A-B-C... D is for dummies.

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Zona

1 year ago

Yeah, D is definitely not the right choice.

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Jutta

1 year ago

I agree, creating sockets is as easy as A-B-C.

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Cecilia

1 year ago

I think A is the correct option.

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Sommer

1 year ago

I'm going with B. It's simple and straight to the point, just like my coding style.

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Sanda

1 year ago

User 3: B sounds good to me, simple is always better.

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Adell

1 year ago

User 2: I'm going with C, it seems more comprehensive.

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Novella

1 year ago

User 1: I think A is the correct answer.

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Percy

1 year ago

D is clearly the wrong answer. You can't create a socket by just passing the server address. That doesn't make any sense.

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Jamal

1 year ago

I think C is the correct answer. The socket.socket() function takes three arguments: the socket domain, socket type, and the server address.

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Aleisha

1 year ago

Actually, B) socket = socket. socket (socket_number) is the correct answer.

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Casie

1 year ago

I'm pretty sure it's D) socket = socket.socket(server address).

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Nan

1 year ago

No, I think it's A) socket. socket (socket_domain, socket_type).

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Annamae

1 year ago

I agree, C is the correct answer.

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Carline

1 year ago

Option A looks right to me. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Caprice

1 year ago

Great, thanks for clarifying that!

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Xuan

1 year ago

So, the correct invocation is socket.socket(socket_domain, socket_type).

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Jess

1 year ago

User 2: Yes, that's correct. The socket module has a function called socket() that takes the socket domain and type as arguments.

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Jodi

1 year ago

Yes, I agree. The socket module's socket() function takes the domain and type as arguments.

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Margot

1 year ago

I think option A is correct.

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Maxima

1 year ago

User 1: I think the answer is A) socket. socket (socket_domain, socket_type)

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Katie

1 year ago

I'm not sure, but I think D) socket = socket.socket(server address) doesn't seem right

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Miriam

1 year ago

I believe it's C) socket = socket.socket(socket_domain, socket_type, server_address)

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Ludivina

1 year ago

I think the answer is A) socket.socket(socket_domain, socket_type)

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