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Python Institute Exam PCPP-32-101 Topic 8 Question 34 Discussion

Actual exam question for Python Institute's PCPP-32-101 exam
Question #: 34
Topic #: 8
[All PCPP-32-101 Questions]

A socket object is usually created by which one of the following invocations?

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Suggested Answer: D

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This statement is true because ElementTree is a module in the standard library of Python that provides an API for working with XML data. The module supports parsing XML from strings or files, creating XML trees from scratch or modifying existing ones, searching and iterating over XML elements, and writing XML data to strings or files.

by Zita at Sep 13, 2024, 02:04 AM

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Penney
22 days ago
Option A, because creating sockets is as easy as A-B-C... D is for dummies.
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Sommer
28 days ago
I'm going with B. It's simple and straight to the point, just like my coding style.
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Percy
29 days ago
D is clearly the wrong answer. You can't create a socket by just passing the server address. That doesn't make any sense.
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Jamal
1 months ago
I think C is the correct answer. The socket.socket() function takes three arguments: the socket domain, socket type, and the server address.
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Casie
2 days ago
I'm pretty sure it's D) socket = socket.socket(server address).
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Nan
13 days ago
No, I think it's A) socket. socket (socket_domain, socket_type).
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Annamae
1 months ago
I agree, C is the correct answer.
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Carline
2 months ago
Option A looks right to me. The socket module has a function called socket() that takes the socket domain and type as arguments.
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Caprice
8 days ago
Great, thanks for clarifying that!
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Xuan
11 days ago
So, the correct invocation is socket.socket(socket_domain, socket_type).
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Jess
19 days ago
User 2: Yes, that's correct. The socket module has a function called socket() that takes the socket domain and type as arguments.
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Jodi
19 days ago
Yes, I agree. The socket module's socket() function takes the domain and type as arguments.
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Margot
21 days ago
I think option A is correct.
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Maxima
21 days ago
User 1: I think the answer is A) socket. socket (socket_domain, socket_type)
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Katie
2 months ago
I'm not sure, but I think D) socket = socket.socket(server address) doesn't seem right
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Miriam
2 months ago
I believe it's C) socket = socket.socket(socket_domain, socket_type, server_address)
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Ludivina
2 months ago
I think the answer is A) socket.socket(socket_domain, socket_type)
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