Python Institute PCEP-30-02 Exam - Topic 2 Question 26 Discussion

Actual exam question for Python Institute's PCEP-30-02 exam

Question #: 26
Topic #: 2

[All PCEP-30-02 Questions]

What happens when the user runs the following code?

AThe program outputs three asterisks ( *** )to the screen.

BThe program outputs one asterisk ( * ) to the screen.

CThe program outputs five asterisks ( ***** ) to the screen.

DThe program enters an infinite loop.

Show Suggested Answer

Suggested Answer: A

Python is an interpreted programming language, which means that the source code is translated into executable code by an interpreter at runtime, rather than by a compiler beforehand. Interpreted languages are more flexible and portable than compiled languages, but they are also slower and less efficient. Assembly and machine languages are low-level languages that are directly executed by the hardware, while compiled languages are high-level languages that are translated into machine code by a compiler before execution.

by Brock at Sep 17, 2024, 12:39 AM

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Pamella

3 months ago

Definitely not an infinite loop, that's for sure!

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Wade

3 months ago

Nah, I think it’s three asterisks ( *** ).

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Alecia

4 months ago

Wait, how can it only print one? Seems off.

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Merissa

4 months ago

Totally agree, option B is correct!

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Basilia

4 months ago

It outputs one asterisk ( * ).

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Anastacia

4 months ago

I think the answer is C, five asterisks. I practiced a question like this where the output depended on a loop counter.

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Kati

4 months ago

I'm not entirely sure, but I remember something about loops in this context. Could it be an infinite loop?

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Carmelina

5 months ago

I feel like I've seen a similar question where the output was just one asterisk. Maybe it's option B?

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Royce

5 months ago

I think the code is supposed to print a certain number of asterisks, but I can't remember if it's three or five.

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Cortney

5 months ago

This is a tricky one. I'm not entirely sure what the code is doing, but I'll give it my best shot. Gotta stay calm and focus on the details.

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Elin

5 months ago

Okay, I've got a strategy here. I'm going to visualize the code execution and try to predict the output. That should help me narrow down the options.

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Pauline

5 months ago

Hmm, I'm a bit confused by this one. The image doesn't seem to match the code, so I'm not sure what to expect. I'll have to think it through step-by-step.

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Magnolia

5 months ago

I think I can figure this out. The code looks pretty straightforward, so I'll just carefully read through the options and see which one makes the most sense.

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Tula

10 months ago

This question is a real head-scratcher! Maybe the code is secretly a portal to another dimension, and the output is just a figment of our imagination. Just kidding, but I'm still scratching my head on this one.

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Franklyn

10 months ago

Ah, I see what's going on here. The answer is B. The code outputs 2. The loop increments i, but it's never used in the loop body, so it just runs twice and outputs 2.

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Noemi

9 months ago

That makes sense. The code doesn't use the incremented i value, so it just outputs 2.

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Beckie

9 months ago

Yes, you're right. The loop runs twice and outputs 2.

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Patria

9 months ago

I think the answer is B. The code outputs 2.

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Cristal

10 months ago

Hmm, I'm not sure. The code looks a bit confusing. Maybe it's an infinite loop? C seems like the right answer to me.

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Ruby

10 months ago

I'm pretty sure the answer is D. The code outputs 1. The loop condition checks if i is less than 3, and the loop body increments i by 1, but the variable i is never used in the loop body, so it will only run once and output 1.

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Amber

9 months ago

Yes, the correct answer is D. The loop will run once and output 1.

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Katy

9 months ago

I believe the answer is D as well. The loop will only run once and output 1.

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Nelida

10 months ago

I think you're right. The code will output 1 because the loop only runs once.

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Sharee

10 months ago

I think the answer is B. The code outputs 2. The loop condition checks if i is less than 3, and the loop body increments i by 1, so the loop will run twice and output 2.

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