OutSystems Associate-Reactive-Developer Exam - Topic 1 Question 18 Discussion

Actual exam question for OutSystems's Associate-Reactive-Developer exam

Question #: 18
Topic #: 1

[All Associate-Reactive-Developer Questions]

Consider the following Action (https://drive.google.com/file/d/1L6qUwd2jjqWAluUB-Kv5gQghendWoMr2/view?usp=sharing), that calculates the square root (sqrt) of a positive decimal number (N). Knowing that the function was called with N = 0, and the debugger is stopped at the Start node, what will happen when the developer selects the Continue (F9) option highlighted in the picture?

AThe Action will end, with sqrt = 0.

BThe Action will throw an exception and sqrt will have no value.

CThe debugger will stop in the N < 0 If node.

DThe debugger will stop at the breakpoint in the End node.

Show Suggested Answer

Suggested Answer: C

by Ryan at Mar 09, 2024, 09:21 PM

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Yan

3 months ago

No way, it definitely throws an exception!

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Amber

4 months ago

I think it should stop at the breakpoint in the End node.

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Kayleigh

4 months ago

Wait, isn't sqrt(0) just 0?

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Micaela

4 months ago

Totally agree, can't take sqrt of 0!

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Emilio

4 months ago

The Action will throw an exception and sqrt will have no value.

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Heike

4 months ago

I’m leaning towards the Action ending with sqrt = 0, but I’m not completely confident about how exceptions are handled in this case.

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Lili

5 months ago

I feel like the debugger might stop at the N < 0 If node, but I can't recall if it checks for 0 specifically.

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Orville

5 months ago

I remember practicing a similar question where the function returned an error for negative inputs, but I'm not sure if 0 counts as negative.

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Fletcher

5 months ago

I think if N is 0, the Action might throw an exception since sqrt of 0 isn't really a positive number.

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Marleen

5 months ago

I've got a strategy for this. Since N is 0, the function should just return 0 as the square root. I'll select Continue and see if that's the case.

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Avery

5 months ago

Okay, the question says the function was called with N = 0, and the debugger is stopped at the Start node. I think the key is to figure out what will happen when I select Continue (F9).

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Ocie

5 months ago

Hmm, this looks tricky. I'll need to carefully read through the code and the question to understand what's happening.

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Gary

5 months ago

I'm a bit confused here. If N is 0, will the function still try to calculate the square root? I'll need to think through the logic step-by-step.

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Taryn

5 months ago

I've got a good strategy for this. I'll start by considering the potential impact of each alert - data deletion and SQL injection are the most severe, so those should be the top priorities. Brute-force attempts are also high-risk, but the firewall alert is probably the least critical, so I'll go with that as the answer.

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Pura

5 months ago

Easy peasy! The hedge fund's legal claim is the $100m notional value of the swap, since the bank failed to make the final monthly payment. No need to overthink this one.

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Susana

10 months ago

I'm going with option B - it's gotta throw an exception. I mean, come on, dividing by zero? That's like the first thing they teach you in programming 101. Although, I'd love to see the developer's face if the debugger just shrugged and stopped at the N < 0 node. That would be a real 'mic drop' moment.

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Shantay

8 months ago

That would be pretty unexpected, but also kind of funny.

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Rene

8 months ago

I'm not so sure, what if it stops at the N < 0 node instead?

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Bo

9 months ago

Yeah, definitely. It's a rookie mistake.

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Demetra

9 months ago

I think it will throw an exception too. Dividing by zero is a big no-no.

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Chantell

10 months ago

Option D seems like the safest bet. The debugger will stop at the breakpoint in the End node, which is the responsible thing to do. But you know what they say, 'expect the unexpected' - maybe the action will just explode and leave the developer scratching their head.

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Jacquelyne

9 months ago

Let's hope for the best and be ready for the worst.

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Malcom

9 months ago

Yeah, I agree. It's always good to be prepared for unexpected errors.

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Rosita

9 months ago

I think option D is the most likely outcome.

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Lisha

10 months ago

Hmm, I'm leaning towards option C. If N is 0, the debugger should stop at the N < 0 node, right? That's the logical choice. Although, I can't help but wonder if the developer secretly programmed in a surprise ending where the action just ends with sqrt = 0.

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Amie

9 months ago

Yeah, it makes sense considering N is 0. The developer probably set it up that way.

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Delbert

9 months ago

I agree, that seems like the logical outcome based on the information provided.

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Lisha

10 months ago

I think option C is the correct choice. The debugger will stop at the N < 0 If node.

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Jerlene

11 months ago

I think option B is the way to go. Dividing by zero is a big no-no, so it's gotta throw an exception. Although, it'd be pretty funny if the debugger just stopped at the N < 0 node instead. What is this, amateur hour?

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Marica

9 months ago

I think the debugger stopping at the N < 0 node would be a bit unexpected. But hey, anything can happen in coding, right?

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Yvonne

10 months ago

Yeah, throwing an exception makes sense. Can't have undefined values floating around.

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Wenona

10 months ago

Well, we'll have to wait and see. It could go either way.

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William

10 months ago

I'm not so sure, I think the debugger might just stop at the N < 0 node instead.

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Suzan

10 months ago

I agree, option B seems like the most logical choice. Dividing by zero is a definite no-go.

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Nell

10 months ago

Yeah, I think so too. It's a common mistake that would definitely throw an exception.

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Anglea

10 months ago

I agree, option B seems most likely. Dividing by zero is a definite exception.

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Shelton

11 months ago

Well, if N is 0, then the square root should be 0, so option A seems correct. But I wonder what happens if N is negative - will it throw an exception or just stop at the N < 0 node?

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