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OutSystems Associate-Reactive-Developer Exam - Topic 1 Question 18 Discussion

Consider the following Action (https://drive.google.com/file/d/1L6qUwd2jjqWAluUB-Kv5gQghendWoMr2/view?usp=sharing), that calculates the square root (sqrt) of a positive decimal number (N). Knowing that the function was called with N = 0, and the debugger is stopped at the Start node, what will happen when the developer selects the Continue (F9) option highlighted in the picture?
C) The debugger will stop in the N < 0 If node.
A) The Action will end, with sqrt = 0.
B) The Action will throw an exception and sqrt will have no value.
D) The debugger will stop at the breakpoint in the End node.

OutSystems Associate-Reactive-Developer Exam - Topic 1 Question 18 Discussion

Actual exam question for OutSystems's Associate-Reactive-Developer exam
Question #: 18
Topic #: 1
[All Associate-Reactive-Developer Questions]

Consider the following Action (https://drive.google.com/file/d/1L6qUwd2jjqWAluUB-Kv5gQghendWoMr2/view?usp=sharing), that calculates the square root (sqrt) of a positive decimal number (N). Knowing that the function was called with N = 0, and the debugger is stopped at the Start node, what will happen when the developer selects the Continue (F9) option highlighted in the picture?

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Suggested Answer: C

by Ryan at Mar 09, 2024, 09:21 PM

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Yan
6 months ago
No way, it definitely throws an exception!
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Amber
7 months ago
I think it should stop at the breakpoint in the End node.
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Kayleigh
7 months ago
Wait, isn't sqrt(0) just 0?
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Micaela
7 months ago
Totally agree, can't take sqrt of 0!
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Emilio
7 months ago
The Action will throw an exception and sqrt will have no value.
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Heike
7 months ago
I’m leaning towards the Action ending with sqrt = 0, but I’m not completely confident about how exceptions are handled in this case.
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Lili
8 months ago
I feel like the debugger might stop at the N < 0 If node, but I can't recall if it checks for 0 specifically.
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Orville
8 months ago
I remember practicing a similar question where the function returned an error for negative inputs, but I'm not sure if 0 counts as negative.
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Fletcher
8 months ago
I think if N is 0, the Action might throw an exception since sqrt of 0 isn't really a positive number.
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Marleen
8 months ago
I've got a strategy for this. Since N is 0, the function should just return 0 as the square root. I'll select Continue and see if that's the case.
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Avery
8 months ago
Okay, the question says the function was called with N = 0, and the debugger is stopped at the Start node. I think the key is to figure out what will happen when I select Continue (F9).
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Ocie
8 months ago
Hmm, this looks tricky. I'll need to carefully read through the code and the question to understand what's happening.
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Gary
8 months ago
I'm a bit confused here. If N is 0, will the function still try to calculate the square root? I'll need to think through the logic step-by-step.
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Taryn
8 months ago
I've got a good strategy for this. I'll start by considering the potential impact of each alert - data deletion and SQL injection are the most severe, so those should be the top priorities. Brute-force attempts are also high-risk, but the firewall alert is probably the least critical, so I'll go with that as the answer.
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Pura
8 months ago
Easy peasy! The hedge fund's legal claim is the $100m notional value of the swap, since the bank failed to make the final monthly payment. No need to overthink this one.
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Susana
1 year ago
I'm going with option B - it's gotta throw an exception. I mean, come on, dividing by zero? That's like the first thing they teach you in programming 101. Although, I'd love to see the developer's face if the debugger just shrugged and stopped at the N < 0 node. That would be a real 'mic drop' moment.
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Shantay
11 months ago
That would be pretty unexpected, but also kind of funny.
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Rene
11 months ago
I'm not so sure, what if it stops at the N < 0 node instead?
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Bo
12 months ago
Yeah, definitely. It's a rookie mistake.
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Demetra
1 year ago
I think it will throw an exception too. Dividing by zero is a big no-no.
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Chantell
1 year ago
Option D seems like the safest bet. The debugger will stop at the breakpoint in the End node, which is the responsible thing to do. But you know what they say, 'expect the unexpected' - maybe the action will just explode and leave the developer scratching their head.
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Jacquelyne
12 months ago
Let's hope for the best and be ready for the worst.
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Malcom
1 year ago
Yeah, I agree. It's always good to be prepared for unexpected errors.
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Rosita
1 year ago
I think option D is the most likely outcome.
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Lisha
1 year ago
Hmm, I'm leaning towards option C. If N is 0, the debugger should stop at the N < 0 node, right? That's the logical choice. Although, I can't help but wonder if the developer secretly programmed in a surprise ending where the action just ends with sqrt = 0.
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Amie
1 year ago
Yeah, it makes sense considering N is 0. The developer probably set it up that way.
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Delbert
1 year ago
I agree, that seems like the logical outcome based on the information provided.
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Lisha
1 year ago
I think option C is the correct choice. The debugger will stop at the N < 0 If node.
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Jerlene
1 year ago
I think option B is the way to go. Dividing by zero is a big no-no, so it's gotta throw an exception. Although, it'd be pretty funny if the debugger just stopped at the N < 0 node instead. What is this, amateur hour?
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Marica
12 months ago
I think the debugger stopping at the N < 0 node would be a bit unexpected. But hey, anything can happen in coding, right?
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Yvonne
1 year ago
Yeah, throwing an exception makes sense. Can't have undefined values floating around.
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Wenona
1 year ago
Well, we'll have to wait and see. It could go either way.
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William
1 year ago
I'm not so sure, I think the debugger might just stop at the N < 0 node instead.
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Suzan
1 year ago
I agree, option B seems like the most logical choice. Dividing by zero is a definite no-go.
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Nell
1 year ago
Yeah, I think so too. It's a common mistake that would definitely throw an exception.
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Anglea
1 year ago
I agree, option B seems most likely. Dividing by zero is a definite exception.
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Shelton
1 year ago
Well, if N is 0, then the square root should be 0, so option A seems correct. But I wonder what happens if N is negative - will it throw an exception or just stop at the N < 0 node?
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Janna
1 year ago
But if N = 0, the sqrt should be 0, so I think A is correct.
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Nana
1 year ago
I disagree, I believe the correct answer is A.
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Janna
1 year ago
I think the correct answer is B.
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