Choose the correct answer
What does a rate applied to an activity edge specify?
Suggested Answer: B
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46 comments · newest first
MA
Marquetta
10 months ago
Wait, isn't it more about lower bounds? I'm not so sure.
VI
Vinnie
11 months ago
I agree with Lizette, D seems right to me.
GR
Gracie
11 months ago
Surprised that people are confused about this! It's pretty straightforward.
AD
Adrianna
11 months ago
I think it's actually the expected changes to an object's value.
LI
Lizette
11 months ago
It's definitely about the expected number of objects traversing the edge.
IV
Ivette
12 months ago
I feel like the answer has to do with the expected number of objects traversing the edge, so I'm leaning towards option D. It just makes sense in the context of flow.
CU
Curt
12 months ago
I’m a bit confused. I thought rates were more about limits, like upper bounds, but I can't recall the exact details.
EL
Eladia
12 months ago
I remember practicing a question like this where we discussed how rates could indicate expected changes over time. I feel like option C might be the right choice.
HE
Herminia
1 year ago
I think a rate on an activity edge might relate to how many objects pass through, but I'm not entirely sure if it's about expected numbers or lower bounds.
EL
Elly
1 year ago
I'm not totally confident, but I'm leaning towards option D. The rate seems to be related to the expected number of traversals.
NA
Nadine
1 year ago
Okay, I think I know the answer. A rate applied to an activity edge specifies the expected number of objects that traverse the edge per time interval.
LA
Lachelle
1 year ago
Hmm, I'm a bit unsure about this. I'll have to review the material on activity edges and rates.
ST
Stephaine
1 year ago
This looks like a tricky one. I'll need to think it through carefully.
BO
Boris
1 year ago
This question is testing our understanding of activity edges and rates. I'll need to double-check my notes to make sure I have the right approach.
CA
Caitlin
1 year ago
Hmm, I'm a bit unsure about this one. The options seem to cover a range of decision-making scenarios, but I'm not sure which one specifically relates to Next-Best-Action.
SH
Sharika
1 year ago
I feel like we've had practice questions about this, and dangerous permissions seem to require user consent. So, it must be normal permissions.
FR
Franchesca
1 year ago
I'm pretty sure the answer is A. Mechanisms based on IP addresses are problematic for mobile users since their IP addresses can change frequently as they move between networks.
TA
Tasia
1 year ago
I'm a little confused by all the different compliance standards mentioned here. I'll need to review my notes on cloud security and government requirements to make sure I understand the differences between these options.
GI
Gilberto
1 year ago
Okay, let me see. The visible spectrum is roughly 400-700 nm, so anything above that should be in the infrared range and not produce visible light. I think the answer is 940 nm.
BE
Benton
1 year ago
If you get stumped, just start randomly bubbling in answers. That's how I aced my driver's license test!
VA
Valda
1 year ago
I think it's F) an upper bound on the number of objects that will traverse the edge per time interval.
MI
Michael
1 year ago
I believe it's A) a lower bound on the number of changes to an object's value per time interval.
SY
Sylvie
1 year ago
I'm not sure, but I think it might be D) the expected number of objects that traverse the edge per time interval.
MI
Mike
1 year ago
I think the correct answer is C) the expected number of changes to an object's value per time interval.
GA
Gail
1 year ago
Hold on, why aren't there any options for the rate being a constant value? That would be my pick, but I guess the exam writers wanted to make this more complicated.
FA
Fallon
1 year ago
User 3: Maybe it's an upper bound on the number of changes to an object's value per time interval.
RO
Rodney
1 year ago
User 2: I believe it's actually the expected number of objects that traverse the edge per time interval.
KA
Kanisha
1 year ago
User 1: I think the rate applied to an activity edge specifies the expected number of changes to an object's value per time interval.
JU
Jules
1 year ago
Hmm, this is a tricky one. I'm going to go with Option F - an upper bound on the number of objects traversing the edge. Seems more realistic than expecting an exact number.
RE
Renea
1 year ago
User4: I think it's option A - a lower bound on the number of changes to an object's value per time interval.
GR
Graciela
1 year ago
User 3: I agree, it allows for some flexibility in the estimation.
JI
Jill
1 year ago
User 2: Yeah, it makes sense to have an upper bound rather than an exact number.
RO
Rolland
1 year ago
User3: I'm not sure, but I'll go with option F - an upper bound on the number of objects that will traverse the edge per time interval.
TE
Tegan
1 year ago
User 1: I think it's Option F too.
BR
Brendan
1 year ago
User2: I disagree, I believe it's option D - the expected number of objects that traverse the edge per time interval.
RU
Rusty
1 year ago
User1: I think it's option C - the expected number of changes to an object's value per time interval.
PA
Paola
1 year ago
I'm leaning towards Option C. The rate should represent the expected number of changes to an object's value, not the number of objects traversing the edge.
LI
Lisandra
1 year ago
Option D seems the most logical choice here. The rate on an activity edge should specify the expected number of objects traversing the edge per time interval.
XO
Xochitl
1 year ago
Yes, I agree. Option D is the most logical choice for the rate applied to an activity edge.
CR
Craig
1 year ago
I think option D is correct. It specifies the expected number of objects that traverse the edge per time interval.
LA
Laticia
2 years ago
I'm not sure, but I think it might be D. Can someone explain why C is the correct answer?
MA
Mammie
2 years ago
I agree with Detra, because the rate applied to an activity edge specifies the expected number of changes to an object's value per time interval.
DE
Detra
2 years ago
I think the correct answer is C.
CE
Celeste
2 years ago
Why do you think it's D?
CR
Cristal
2 years ago
I disagree, I believe it's D.
CE
Celeste
2 years ago
I think the answer is C.