Nokia 4A0-255 Exam - Topic 3 Question 41 Discussion

Actual exam question for Nokia's 4A0-255 exam

Question #: 41
Topic #: 3

[All 4A0-255 Questions]

Consider the exhibit. Which of the following NE architectures is represented?

ATOADm

B(Classic) ROADM

CC-F ROADM

DCDC-F ROADm

Show Suggested Answer

Suggested Answer: A

by Brinda at May 20, 2024, 03:54 AM

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Earlean

3 months ago

Wait, are we sure about this? Looks different than what I expected.

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Kirk

3 months ago

I disagree, it’s clearly a CDC-F ROADM.

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Myra

3 months ago

I think it's a Classic ROADM, not sure though.

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Gerardo

4 months ago

Definitely a TOADm architecture!

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Virgina

4 months ago

Looks like a C-F ROADM to me.

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Stephaine

4 months ago

I have a hunch it's a C-F ROADM, but I could be mixing it up with the classic version.

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Freeman

4 months ago

This question reminds me of a practice exam where we had to identify different NE architectures. I feel like it's definitely a ROADM variant.

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Tesha

4 months ago

I remember studying about ROADMs, but I can't recall the differences between C-F and CDC-F ROADMs.

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Hyman

5 months ago

I think the image looks familiar, but I'm not entirely sure if it's a TOADm or a ROADM.

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Audry

5 months ago

Based on the components I can see in the image, I believe this represents a CDC-F ROADM architecture, so I'll select option D.

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Clorinda

5 months ago

The options mention some unfamiliar terms like "TOADm" and "C-F ROADM." I'm not sure what those are, so I'll have to guess on this one.

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Krystina

5 months ago

The image shows a wavelength-selective switch, which is a key component of ROADM systems. I think option B is the correct answer.

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Lourdes

5 months ago

Hmm, I'm not too familiar with these NE architectures. I'll have to carefully examine the image and options to try to figure this out.

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Ranee

5 months ago

This looks like a classic ROADM architecture, so I'll go with option B.

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Marion

5 months ago

This seems like a pretty straightforward question. I think the answer is C - creating a mount unit and enabling it to start at boot would be the best way to prevent this issue from happening again.

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Vanda

5 months ago

Hmm, this looks like a tricky one. I'll need to carefully read through the options and think about what I know about node access groups.

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Mickie

5 months ago

I'm not entirely sure about this, but I believe Geth is used by other nodes like Parity, even though it's closed-source. So I'm leaning towards option B.

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Mike

5 months ago

This seems pretty straightforward. The company has a liability insurance policy, so the answer is clearly risk transfer.

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Darrin

2 years ago

Forget the ROADM, I'm more interested in what's powering that disco ball in the corner!

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Vincenza

2 years ago

C) C-F ROADM

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Shay

2 years ago

B) (Classic) ROADM

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Amie

2 years ago

A) TOADm

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Artie

2 years ago

Definitely the CDC-F ROADm. It's got all the bells and whistles - colorful, confusing, and probably overengineered.

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Lennie

2 years ago

Agreed, the exhibit is definitely showing the CDC-F ROADm architecture.

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Kayleigh

2 years ago

Yeah, definitely looks like it has a lot going on.

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Kimberlie

2 years ago

I think it's the CDC-F ROADm too. It looks pretty complex.

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Mireya

2 years ago

Hmm, I'm not sure. The image doesn't seem to match the descriptions perfectly. Could be a trick question?

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Lizbeth

2 years ago

I agree, the architecture in the exhibit does resemble a C-F ROADM.

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Jamal

2 years ago

I think it looks like a C-F ROADM.

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Tran

2 years ago

I agree, the exhibit does seem to match that architecture.

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Ollie

2 years ago

I think it might be (Classic) ROADM.

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Franklyn

2 years ago

I'm leaning towards TOADm, but I see what you mean about it not matching perfectly.

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Joaquin

2 years ago

I think it might be a C-F ROADM.

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Emeline

2 years ago

I'm going with C-F ROADM. The grid of colored squares suggests the CDC-F architecture.

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Beckie

2 years ago

This looks like a classic ROADM to me. The diagram shows the wavelength selective switching characteristic.

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Margurite

2 years ago

I still think B) (Classic) ROADM is the best fit based on the diagram.

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Arlette

2 years ago

I'm leaning towards C) C-F ROADM, what do you think?

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Emogene

2 years ago

Definitely not A) TOADm, that wouldn't have the wavelength selective switching.

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Launa

2 years ago

That makes sense, the diagram matches the characteristics of a classic ROADM.

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Zana

2 years ago

I think the answer is B) (Classic) ROADM.

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Lashaun

2 years ago

Yes, the wavelength selective switching is a key feature of a classic ROADM.

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Clarence

2 years ago

I agree, it does look like a classic ROADM.

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Sharmaine

2 years ago

Yes, I agree. The wavelength selective switching is a key feature of a classic ROADM.

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Dominga

2 years ago

I think you're right, it does look like a classic ROADM.

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