Nokia Exam 4A0-116 Topic 8 Question 14 Discussion

Actual exam question for Nokia's 4A0-116 exam

Question #: 14
Topic #: 8

An SR-TE LSP with a path definition that includes router R4 as a loose hop and for which Seamless-BFD has been enabled is following the path shown in the exhibit. What happens after router R4 fails if the routers along the path follow the default behavior?

AThe head end will periodically try to calculate a new path at a rate defined by the retry timer.

BThe head end will periodically try to calculate a new path at a rate defined by the resignal timer.

CThe head end will continue forwarding traffic to the current next-hop indefinitely, which will be discarded at the point of failure.

DThe head end will continue forwarding traffic to the current next-hop indefinitely, and R2 will redirect the traffic to R3 after IGP reconvergence.

Show Suggested Answer

Suggested Answer: D

by Iluminada at Aug 08, 2023, 01:23 PM

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Pauline

1 months ago

Ah, the joys of routing protocols and path calculations. If only we could all just forward traffic to the nearest dumpster fire and call it a day. But alas, the network gods demand more from us.

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Sommer

1 days ago

C) The head end will continue forwarding traffic to the current next-hop indefinitely, which will be discarded at the point of failure.

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Jacki

17 days ago

A) The head end will periodically try to calculate a new path at a rate defined by the retry timer.

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Desmond

2 months ago

This is a tricky one, but I think B is the correct answer. The question mentions Seamless-BFD, so the head end will likely try to recalculate the path at a rate defined by the resignal timer. I hope I'm right, or else I'll need to resign myself to a poor score on this exam.

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Cammy

27 days ago

User1: Hopefully we're right, otherwise we might need to study this topic more for the exam.

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Erasmo

1 months ago

User2: I agree, Seamless-BFD will trigger the head end to try to find a new path after R4 fails.

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Howard

2 months ago

User1: I think B is the correct answer too. The head end will recalculate the path at a rate defined by the resignal timer.

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Daniel

2 months ago

I'm going with C. The head end will continue forwarding traffic to the current next-hop indefinitely, which will be discarded at the point of failure. It's the simplest and most straightforward option.

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Hildred

2 months ago

But if R4 fails, the head end will continue forwarding traffic to the current next-hop indefinitely, and R2 will redirect the traffic to R3 after IGP reconvergence, so I think D makes more sense.

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Charisse

2 months ago

I'm pretty sure the answer is D. The head end will continue forwarding traffic to the current next-hop indefinitely, and R2 will redirect the traffic to R3 after IGP reconvergence. That makes the most sense to me.

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Idella

23 days ago

I'm pretty sure the answer is D. The head end will continue forwarding traffic to the current next-hop indefinitely, and R2 will redirect the traffic to R3 after IGP reconvergence.

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Refugia

1 months ago

Actually, I think it's B. The head end will periodically try to calculate a new path at a rate defined by the resignal timer.

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Sanda

2 months ago

I disagree, I believe the answer is C. The head end will continue forwarding traffic to the current next-hop indefinitely, which will be discarded at the point of failure.

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Gregg

2 months ago

I think the answer is A. The head end will periodically try to calculate a new path at a rate defined by the retry timer.

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Marshall

2 months ago

The answer is B, the head end will periodically try to calculate a new path at a rate defined by the resignal timer. This is because the question mentions that the path definition includes a loose hop, so the head end will need to recalculate the path after the failure of R4.

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Yolando

2 months ago

I disagree, I believe the correct answer is D.

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Hildred

3 months ago

I think the answer is C.

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