Nokia 4A0-113 Exam - Topic 4 Question 23 Discussion

Actual exam question for Nokia's 4A0-113 exam

Question #: 23
Topic #: 4

[All 4A0-113 Questions]

What command could be used to verify proper configuration of a static route in an Nokia 7750 SR router?

AShow route-table

BShow router routing-table

CShow router route-table

DShow static

Show Suggested Answer

Suggested Answer: C

by Dorothy at May 05, 2022, 10:42 PM

Limited Time Offer

25%

Off

Get Premium 4A0-113 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Leslee

4 months ago

Definitely not "Show static", that's not a valid command.

upvoted 0 times

...

Lenna

4 months ago

Wait, can you really use "Show static" for that? Sounds weird!

upvoted 0 times

...

Olen

4 months ago

"Show router route-table" seems off to me.

upvoted 0 times

...

Johnna

4 months ago

I think "Show router routing-table" is the right one.

upvoted 0 times

...

France

4 months ago

Pretty sure it's "Show route-table".

upvoted 0 times

...

Becky

5 months ago

I feel like "show router route-table" could be the right one, but I can't recall if there's a specific command for static routes.

upvoted 0 times

...

Lashon

5 months ago

I remember practicing with similar questions, and "show router routing-table" sounds familiar, but it could be a trick.

upvoted 0 times

...

Luis

5 months ago

I think the command might be "show route-table," but I'm not entirely sure if that's the exact syntax for the Nokia 7750 SR.

upvoted 0 times

...

Sage

5 months ago

I thought "show static" was related to static routes, but I don't know if it verifies the configuration like the others might.

upvoted 0 times

...

Wilbert

5 months ago

I'm a bit confused by the last option, "DOMW Courier Newlr Z." That doesn't sound like a real XML-based technology to me. I'll focus on the more obvious choices.

upvoted 0 times

...

Deeann

5 months ago

I remember something about the standard deviation of averages being related to the original standard deviation divided by the sample size, so maybe statement II is correct.

upvoted 0 times

...