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Nokia Exam 4A0-103 Topic 3 Question 80 Discussion

Actual exam question for Nokia's 4A0-103 exam
Question #: 80
Topic #: 3
[All 4A0-103 Questions]

Click on the exhibit.

An LSP's primary path takes R1-R3-R5-R6. Its fully loose secondary path is configured for SRLG. All links are of equal cost. Which path will the secondary path take?

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Suggested Answer: B

Contribute your Thoughts:

Jame
1 months ago
I'm going to go with B, because it's the shortest path that avoids the SRLG of the primary path. Unless, of course, the exam writer is a fan of the Traveling Salesman Problem. Then all bets are off!
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Jacquelyne
1 months ago
Wait, does R2 stand for 'router 2' or 'R2-D2'? I'm going with B, just in case it's the latter and I need to avoid any potential droid malfunctions.
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Janae
17 days ago
User 3: Good call, let's avoid any potential droid malfunctions.
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Beth
20 days ago
User 2: Yeah, I agree. Let's go with option B.
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Lawana
22 days ago
User 1: I think R2 stands for 'router 2'.
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Heidy
2 months ago
Ah, this is a tricky one! I'm going to guess C, just to be different. Who knows, maybe the exam writer has a wicked sense of humor.
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Valentine
4 days ago
User3: I'm going with option C too, just to mix it up.
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Delisa
7 days ago
User2: I believe the secondary path will take R1-R2-R3-R5-R6.
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Ramonita
9 days ago
User1: I think the secondary path will take R1-R2-R4-R6.
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Brandon
2 months ago
D looks good to me. It takes a different path but still avoids the SRLG of the primary path.
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Fatima
3 days ago
Option C goes through R3 which is part of the primary path, so D is a better choice.
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Lelia
5 days ago
But what about option C? It also avoids the SRLG.
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Tomas
11 days ago
I agree, D is the most logical choice for the secondary path in this scenario.
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Edgar
13 days ago
Yeah, D seems like the best option to ensure path diversity.
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Dorinda
15 days ago
I agree, D takes a different path to avoid the SRLG.
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Brande
1 months ago
I think D is the correct answer too. It avoids the SRLG of the primary path.
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Alline
2 months ago
I think D is the correct answer.
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Kirby
2 months ago
I think the answer is B, since the secondary path is configured for SRLG and should avoid the SRLG of the primary path.
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Art
2 months ago
But the primary path is R1-R3-R5-R6, so the secondary path should avoid those links. I still think it's R1-R3-R2-R4-R5-R6.
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Staci
2 months ago
I believe the secondary path will take R1-R2-R4-R6.
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Art
2 months ago
I think the secondary path will take R1-R3-R2-R4-R5-R6.
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Micaela
3 months ago
But the question mentions that all links are of equal cost, so the secondary path should be the shortest one, which is R1-R2-R4-R6.
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Beatriz
3 months ago
I disagree, I believe the secondary path will take R1-R2-R4-R6.
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Micaela
3 months ago
I think the secondary path will take R1-R3-R2-R4-R6.
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