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Nokia 4A0-103 Exam - Topic 3 Question 80 Discussion

Click on the exhibit.An LSP's primary path takes R1-R3-R5-R6. Its fully loose secondary path is configured for SRLG. All links are of equal cost. Which path will the secondary path take?
B) The secondary path will take R1-R2-R4-R6.
A) The secondary path will take R1-R3-R2-R4-R6.
C) The secondary path will take R1-R2-R3-R5-R6.
D) The secondary path will take R1-R3-R2-R4-R5-R6.

Nokia 4A0-103 Exam - Topic 3 Question 80 Discussion

Actual exam question for Nokia's 4A0-103 exam
Question #: 80
Topic #: 3
[All 4A0-103 Questions]

Click on the exhibit.

An LSP's primary path takes R1-R3-R5-R6. Its fully loose secondary path is configured for SRLG. All links are of equal cost. Which path will the secondary path take?

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Suggested Answer: B

by Fannie at Jan 22, 2024, 06:30 AM

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Clemencia
8 months ago
All links are equal cost? Interesting twist!
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Valentin
8 months ago
I think it should be R1-R2-R4-R6 instead.
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Elly
8 months ago
Wait, why would it take that route? Seems off.
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Hillary
8 months ago
Totally agree with that! Makes sense.
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Jamey
9 months ago
The secondary path will take R1-R3-R2-R4-R6.
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Von
9 months ago
I vaguely remember that the secondary path needs to consider SRLG constraints. I’m torn between A and D, but I think A might be the right choice.
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Oretha
9 months ago
I think the secondary path should take a route that avoids the primary nodes. I’m leaning towards A, but I’m a bit confused about the equal cost links.
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Ilda
9 months ago
This question seems similar to one we practiced where we had to determine alternate paths. I feel like the answer could be B, but I can't recall the specifics about SRLG.
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Gregg
9 months ago
I remember studying about secondary paths and how they should avoid the primary path. I think it might be R1-R3-R2-R4-R6, but I'm not entirely sure.
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Art
9 months ago
Hmm, I'm not sure about this one. I'll need to sketch out the network diagram and carefully consider all the possible paths before making a decision. The SRLG requirement is the key factor here, so I'll need to analyze that closely.
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Brittani
9 months ago
I'm feeling pretty confident about this one. Based on the information provided, I think the secondary path should take R1-R2-R4-R6 to avoid any SRLG with the primary path. That seems like the most logical and efficient solution.
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Dierdre
10 months ago
I'm a bit confused by the SRLG requirement. Does that mean the secondary path needs to be completely disjoint from the primary path? Or can it share some links as long as it avoids the SRLG?
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Arminda
10 months ago
Hmm, this looks like a tricky SRLG routing question. I'll need to carefully analyze the network topology and the primary path to determine the optimal secondary path.
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Kaitlyn
10 months ago
Okay, let me think this through step-by-step. The primary path is R1-R3-R5-R6, and the secondary path should be configured for SRLG. I'll need to consider the available links and avoid any shared risk link groups.
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Francoise
10 months ago
I'm a bit confused on this one. Are price cutting and franchising more appropriate for an embryonic or a declining market? I'll have to review my notes to be sure.
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Kati
10 months ago
Okay, let's see... I know we can use sqlplus to restart the database, but I'm not sure about the exact syntax. I'll need to double-check the options.
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Sherita
10 months ago
I'm a little confused on this one. I know Jumpcloud can manage user accounts, but I'm not sure of the exact behavior when de-provisioning a synced user. I'll have to review the integration details to make sure I understand the right answer.
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Jame
1 year ago
I'm going to go with B, because it's the shortest path that avoids the SRLG of the primary path. Unless, of course, the exam writer is a fan of the Traveling Salesman Problem. Then all bets are off!
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Leslee
1 year ago
I'm leaning towards D, it seems like a safer route to take.
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Hillary
1 year ago
I agree with you, B seems like the most logical choice.
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Micah
1 year ago
I'm not sure, I think C might be a better option.
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Carlee
1 year ago
I think B is the best choice too.
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Jacquelyne
1 year ago
Wait, does R2 stand for 'router 2' or 'R2-D2'? I'm going with B, just in case it's the latter and I need to avoid any potential droid malfunctions.
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Janae
1 year ago
User 3: Good call, let's avoid any potential droid malfunctions.
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Beth
1 year ago
User 2: Yeah, I agree. Let's go with option B.
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Lawana
1 year ago
User 1: I think R2 stands for 'router 2'.
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Heidy
1 year ago
Ah, this is a tricky one! I'm going to guess C, just to be different. Who knows, maybe the exam writer has a wicked sense of humor.
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Valentine
1 year ago
User3: I'm going with option C too, just to mix it up.
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Delisa
1 year ago
User2: I believe the secondary path will take R1-R2-R3-R5-R6.
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Ramonita
1 year ago
User1: I think the secondary path will take R1-R2-R4-R6.
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Brandon
1 year ago
D looks good to me. It takes a different path but still avoids the SRLG of the primary path.
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Fatima
1 year ago
Option C goes through R3 which is part of the primary path, so D is a better choice.
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Lelia
1 year ago
But what about option C? It also avoids the SRLG.
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Tomas
1 year ago
I agree, D is the most logical choice for the secondary path in this scenario.
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Edgar
1 year ago
Yeah, D seems like the best option to ensure path diversity.
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Dorinda
1 year ago
I agree, D takes a different path to avoid the SRLG.
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Brande
1 year ago
I think D is the correct answer too. It avoids the SRLG of the primary path.
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Alline
1 year ago
I think D is the correct answer.
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Kirby
1 year ago
I think the answer is B, since the secondary path is configured for SRLG and should avoid the SRLG of the primary path.
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Art
1 year ago
But the primary path is R1-R3-R5-R6, so the secondary path should avoid those links. I still think it's R1-R3-R2-R4-R5-R6.
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Staci
1 year ago
I believe the secondary path will take R1-R2-R4-R6.
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Art
1 year ago
I think the secondary path will take R1-R3-R2-R4-R5-R6.
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Micaela
1 year ago
But the question mentions that all links are of equal cost, so the secondary path should be the shortest one, which is R1-R2-R4-R6.
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Beatriz
1 year ago
I disagree, I believe the secondary path will take R1-R2-R4-R6.
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Micaela
1 year ago
I think the secondary path will take R1-R3-R2-R4-R6.
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