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Nokia Exam 4A0-102 Topic 6 Question 51 Discussion

Actual exam question for Nokia's 4A0-102 exam
Question #: 51
Topic #: 6
[All 4A0-102 Questions]

Which of the following prefix lists include prefixes 192.168.128.0/17 and 192.168.64.0/18?

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Suggested Answer: B

by Galen at Mar 09, 2024, 09:25 PM

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Mary
1 months ago
I wonder if the exam question writer is a secret stand-up comedian. 'What do you call a network with too many subnets? A sub-optimal network!'
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Harris
1 months ago
Aha, got it! Option C is the answer. Now, if only I could remember how many bits are in an octet... *scratches head*
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Tricia
5 days ago
User 3: Don't worry, an octet has 8 bits.
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Azalee
9 days ago
User 3: Don't worry, an octet has 8 bits.
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Serina
9 days ago
User 2: That's correct!
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Lucy
13 days ago
User 2: That's correct!
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Elfrieda
17 days ago
User 1: Option C) Prefix list 192.168.0.0/17 through 18.
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Sophia
1 months ago
User 1: Option C) Prefix list 192.168.0.0/17 through 18.
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Carrol
2 months ago
This is a piece of cake! The prefixes are clearly mentioned in option C. Time to move on to the next question and show off my networking prowess.
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Erick
28 days ago
Impressive! Keep up the good work.
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Yolande
1 months ago
I knew it was option C. Networking skills on point!
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Wai
2 months ago
Great job! Let's move on to the next question.
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Derick
2 months ago
I agree, option C includes both prefixes 192.168.128.0/17 and 192.168.64.0/18.
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Devorah
2 months ago
Ah, the joy of subnetting! Option C is the way to go, I reckon. Now, where did I leave my binary-to-decimal conversion cheat sheet?
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Moon
2 months ago
Hmm, this looks like a tricky one. I'm going to go with option C, it seems to include the prefixes mentioned in the question.
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Ty
1 months ago
User 2: Yeah, I agree. It includes both prefixes 192.168.128.0/17 and 192.168.64.0/18.
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Felicidad
2 months ago
User 1: I think option C is the right one.
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Jess
2 months ago
I'm not sure, but I think D) Prefix 192.160.0.0/13 longer is incorrect.
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Latia
2 months ago
I agree with Renay, because both prefixes are covered in that range.
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Renay
2 months ago
I think the answer is C) Prefix list 192.168.0.0/17 through 18.
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