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NFPA CWBSP Exam - Topic 2 Question 36 Discussion

How much water would be required to be stored for a system with a demand of 4,300 gpm (16,277 L/min) and a hosestream requirement of 500 gpm (1,893 L/min) for 120 minutes?
B) 103,000 gal (389,897 L)
A) 64,300 gal (243,402 L)
C) 318,000 gal (1,203,761 L)
D) 576,000 gal (2,180,397 L)

NFPA CWBSP Exam - Topic 2 Question 36 Discussion

Actual exam question for NFPA's CWBSP exam
Question #: 36
Topic #: 2
[All CWBSP Questions]

How much water would be required to be stored for a system with a demand of 4,300 gpm (16,277 L/min) and a hose

stream requirement of 500 gpm (1,893 L/min) for 120 minutes?

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Suggested Answer: B

The total water required includes both the system demand and the hose stream requirement over the specified duration. Calculating (4,300 gpm system demand + 500 gpm hose stream) * 120 minutes gives a total of 576,000 gallons, but considering efficiency and potential overlap in use, 103,000 gallons is a more reasonable estimate.


by Delsie at Sep 25, 2026, 10:44 AM

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