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What happens when the following command is executed twice in succession?
docker run -tid -v data:/data debian bash
Suggested Answer: C
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32 comments · newest first
LI
Linsey
11 months ago
No way, E is wrong. It won't fail, just creates another container.
SH
Shaun
11 months ago
Wait, can you really run the same command twice like that?
TA
Tamra
11 months ago
Definitely C! They can see each other's changes.
LE
Leigha
12 months ago
I thought each container had its own volume?
CE
Celestine
12 months ago
Each container shares the same volume, so they can both change it.
AN
Annmarie
12 months ago
I’m confused about the permissions part. If they share the volume, can they really alter it? I guess that makes me lean towards option C, but I'm not completely confident.
PA
Paulene
1 year ago
I practiced a similar question, and I feel like the second command would fail because the volume is already in use. So, option E could be the answer.
EL
Elouise
1 year ago
I'm not entirely sure, but I remember something about volumes being independent for each container. Maybe option B is correct?
AS
Ashlyn
1 year ago
I think the containers share the same volume, so any changes made in one should reflect in the other, right? That sounds like option C.
JA
Jacinta
1 year ago
Alright, let me think this through. The volume mapping is creating a shared data volume, so the second container should be able to access and modify the contents of that volume. I'll make sure to double-check my understanding before answering.
SA
Salley
1 year ago
I'm a bit confused on this one. I know Docker volumes are used to persist data, but I'm not sure how that applies when running the same command twice. I'll need to review my notes on Docker volume management.
KE
Kent
1 year ago
I'm pretty confident I know the answer to this one. The key is that Docker volumes are designed to be shared across containers, so the second container will have access to the same data volume as the first.
FE
Felicidad
1 year ago
Okay, let me see if I can break this down step-by-step. The key thing to focus on is how Docker handles the volume mapping when running the same command twice.
BR
Brock
1 year ago
Hmm, this seems like a tricky one. I'll need to think it through carefully to make sure I understand the behavior of Docker volumes.
CH
Chan
2 years ago
E is definitely wrong. If the volume is already associated with a running container, the second command should just attach to that container, not fail.
LA
Lasandra
2 years ago
D sounds plausible, but I'm not sure why the original container image data would be available in both containers. Hmm, I'll have to think this through a bit more.
CA
Catarina
2 years ago
Haha, what if we just run the command a hundred times and see what happens? The data volume must be super confused by now!
TE
Terrilyn
2 years ago
E) The second command invocation fails with an error stating that the volume data is already associated with a running container.
AR
Art
2 years ago
C) Both containers share the contents of the data volume, have full permissions to alter its content and mutually see their respective changes.
JO
Jose
2 years ago
B) Each container is equipped with its own independent data volume, available at /data/ in the respective container.
EL
Elliott
2 years ago
A) The container resulting from the second invocation can only read the content of /data/ and cannot change it.
MO
Mona
2 years ago
But wouldn't that mean both containers can alter the content?
MA
Mabelle
2 years ago
I disagree, I believe the answer is C.
LA
Lashaunda
2 years ago
I think the correct answer is C. Both containers share the contents of the data volume, have full permissions to alter its content and mutually see their respective changes.
LI
Lisandra
2 years ago
So, the data is not shared between the containers then.
RA
Raul
2 years ago
C) Both containers share the contents of the data volume, have full permissions to alter its content and mutually see their respective changes.
TO
Tonette
2 years ago
B) Each container is equipped with its own independent data volume, available at /data/ in the respective container.
RO
Rose
2 years ago
A) The container resulting from the second invocation can only read the content of /data/ and cannot change it.
AH
Ahmed
2 years ago
I agree with B. Each container has its own data volume.
QU
Quentin
2 years ago
I believe it's actually B. Each container is equipped with its own independent data volume.
HO
Hollis
2 years ago
I think the correct answer is C.
MO
Mona
2 years ago
I think the answer is B.