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Linux Foundation Exam LFCS Topic 7 Question 52 Discussion

Actual exam question for Linux Foundation's LFCS exam
Question #: 52
Topic #: 7
[All LFCS Questions]

What is the difference between the commands test -e path and test -f path?

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Suggested Answer: E

by Filiberto at Jan 08, 2023, 01:02 AM

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Margret
28 days ago
Wait, is this a trick question? I feel like I'm being Schrodinger'd here. I'm just going to go with C and hope for the best.
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Christa
3 days ago
User 2: Yeah, that sounds right. The -e option just checks for existence.
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Blair
15 days ago
User 1: I think the -f option checks for a regular file.
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Hermila
29 days ago
D? Really? That's just silly. I mean, who confuses regular files with executable files these days? Option C is the way to go, folks.
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Rikki
1 months ago
I almost went with A, but then I realized that the options have different behaviors. C is the clear winner here.
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Denny
8 days ago
C is the clear winner here.
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Leota
17 days ago
I almost went with A, but then I realized that the options have different behaviors.
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Lavina
2 months ago
I was a bit confused between the -e and -f options, but after reading the question closely, I think C is the way to go.
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Bernardo
21 days ago
User 2: Yeah, both options check the existence of the path, but -f also confirms it's a regular file.
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Lawrence
24 days ago
User 1: I think C is the correct option.
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Mona
2 months ago
Oh, I see. So -f not only checks for existence but also confirms it's a regular file. That makes sense.
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Danilo
2 months ago
Option C seems to be the correct answer. Both options check for the existence of the path, but -f also confirms that it is a regular file.
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Lezlie
2 months ago
Actually, -f checks for a regular file, and -e checks for the existence of the path. So, -f is more specific.
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Mona
2 months ago
I think the difference is that -f checks for a regular file, while -e checks for an empty file.
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