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Linux Foundation LFCS Exam - Topic 7 Question 52 Discussion

Posted by Filiberto on Jan 08, 2023 at 01:02 AM

What is the difference between the commands test -e path and test -f path?

Suggested Answer: E

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27 comments · newest first
AN
Angella 12 months ago
So basically, -f is a stricter check? Makes sense!
NA
Natalie 1 year ago
Nope, -e just checks if the path exists, not empty or executable.
SH
Shaquana 1 year ago
Wait, I thought -e was for executable files?
WE
Wendell 1 year ago
Totally agree, -f is more specific!
ZA
Zack 1 year ago
The -f option checks for regular files, while -e just checks existence.
CO
Corrie 1 year ago
I thought -e was for executable files, but now I'm confused because I remember it being about existence too.
SA
Sarah 1 year ago
I believe both options check for existence, but -f specifically confirms it's a regular file. That sounds right, doesn't it?
PR
Precious 1 year ago
I remember practicing something similar where -f was about regular files, but I can't recall exactly what -e checks for.
RO
Robt 1 year ago
I think the -e option just checks if the file exists, but I'm not entirely sure what -f does.
GI
Gilma 1 year ago
I'm pretty sure the right answer has to do with security and licensing requirements for Flow. I just need to make sure I understand the details.
LA
Lashandra 1 year ago
The key is focusing on the specific details in the question. A voucher has to include all three elements - the purchase order, vendor invoice, and receiving reports. I think A is the only option that matches that.
LA
Lacresha 1 year ago
Hmm, this one seems tricky. I'll need to think through how Selenium fits into the overall test automation architecture.
MA
Margret 2 years ago
Wait, is this a trick question? I feel like I'm being Schrodinger'd here. I'm just going to go with C and hope for the best.
LA
Laticia 1 year ago
↳ replying to Margret
User 3: So, the -f option also confirms it's a regular file. I'll go with C too.
CH
Christa 1 year ago
↳ replying to Margret
User 2: Yeah, that sounds right. The -e option just checks for existence.
BL
Blair 1 year ago
↳ replying to Margret
User 1: I think the -f option checks for a regular file.
HE
Hermila 2 years ago
D? Really? That's just silly. I mean, who confuses regular files with executable files these days? Option C is the way to go, folks.
RI
Rikki 2 years ago
I almost went with A, but then I realized that the options have different behaviors. C is the clear winner here.
DE
Denny 1 year ago
↳ replying to Rikki
C is the clear winner here.
LE
Leota 1 year ago
↳ replying to Rikki
I almost went with A, but then I realized that the options have different behaviors.
LA
Lavina 2 years ago
I was a bit confused between the -e and -f options, but after reading the question closely, I think C is the way to go.
BE
Bernardo 1 year ago
↳ replying to Lavina
User 2: Yeah, both options check the existence of the path, but -f also confirms it's a regular file.
LA
Lawrence 1 year ago
↳ replying to Lavina
User 1: I think C is the correct option.
MO
Mona 2 years ago
Oh, I see. So -f not only checks for existence but also confirms it's a regular file. That makes sense.
DA
Danilo 2 years ago
Option C seems to be the correct answer. Both options check for the existence of the path, but -f also confirms that it is a regular file.
LE
Lezlie 2 years ago
Actually, -f checks for a regular file, and -e checks for the existence of the path. So, -f is more specific.
MO
Mona 2 years ago
I think the difference is that -f checks for a regular file, while -e checks for an empty file.
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