Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Linux Foundation LFCS Exam - Topic 7 Question 52 Discussion

Actual exam question for Linux Foundation's LFCS exam
Question #: 52
Topic #: 7
[All LFCS Questions]

What is the difference between the commands test -e path and test -f path?

Show Suggested Answer Hide Answer
Suggested Answer: E

by Filiberto at Jan 08, 2023, 01:02 AM

Limited Time Offer

25%

Off

Get Premium LFCS Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Angella
4 months ago
So basically, -f is a stricter check? Makes sense!
upvoted 0 times
...
Natalie
5 months ago
Nope, -e just checks if the path exists, not empty or executable.
upvoted 0 times
...
Shaquana
5 months ago
Wait, I thought -e was for executable files?
upvoted 0 times
...
Wendell
5 months ago
Totally agree, -f is more specific!
upvoted 0 times
...
Zack
5 months ago
The -f option checks for regular files, while -e just checks existence.
upvoted 0 times
...
Corrie
5 months ago
I thought -e was for executable files, but now I'm confused because I remember it being about existence too.
upvoted 0 times
...
Sarah
5 months ago
I believe both options check for existence, but -f specifically confirms it's a regular file. That sounds right, doesn't it?
upvoted 0 times
...
Precious
5 months ago
I remember practicing something similar where -f was about regular files, but I can't recall exactly what -e checks for.
upvoted 0 times
...
Robt
5 months ago
I think the -e option just checks if the file exists, but I'm not entirely sure what -f does.
upvoted 0 times
...
Gilma
6 months ago
I'm pretty sure the right answer has to do with security and licensing requirements for Flow. I just need to make sure I understand the details.
upvoted 0 times
...
Lashandra
6 months ago
The key is focusing on the specific details in the question. A voucher has to include all three elements - the purchase order, vendor invoice, and receiving reports. I think A is the only option that matches that.
upvoted 0 times
...
Lacresha
6 months ago
Hmm, this one seems tricky. I'll need to think through how Selenium fits into the overall test automation architecture.
upvoted 0 times
...
Margret
11 months ago
Wait, is this a trick question? I feel like I'm being Schrodinger'd here. I'm just going to go with C and hope for the best.
upvoted 0 times
Laticia
10 months ago
User 3: So, the -f option also confirms it's a regular file. I'll go with C too.
upvoted 0 times
...
Christa
10 months ago
User 2: Yeah, that sounds right. The -e option just checks for existence.
upvoted 0 times
...
Blair
10 months ago
User 1: I think the -f option checks for a regular file.
upvoted 0 times
...
...
Hermila
11 months ago
D? Really? That's just silly. I mean, who confuses regular files with executable files these days? Option C is the way to go, folks.
upvoted 0 times
...
Rikki
11 months ago
I almost went with A, but then I realized that the options have different behaviors. C is the clear winner here.
upvoted 0 times
Denny
10 months ago
C is the clear winner here.
upvoted 0 times
...
Leota
10 months ago
I almost went with A, but then I realized that the options have different behaviors.
upvoted 0 times
...
...
Lavina
11 months ago
I was a bit confused between the -e and -f options, but after reading the question closely, I think C is the way to go.
upvoted 0 times
Bernardo
10 months ago
User 2: Yeah, both options check the existence of the path, but -f also confirms it's a regular file.
upvoted 0 times
...
Lawrence
10 months ago
User 1: I think C is the correct option.
upvoted 0 times
...
...
Mona
11 months ago
Oh, I see. So -f not only checks for existence but also confirms it's a regular file. That makes sense.
upvoted 0 times
...
Danilo
11 months ago
Option C seems to be the correct answer. Both options check for the existence of the path, but -f also confirms that it is a regular file.
upvoted 0 times
...
Lezlie
11 months ago
Actually, -f checks for a regular file, and -e checks for the existence of the path. So, -f is more specific.
upvoted 0 times
...
Mona
11 months ago
I think the difference is that -f checks for a regular file, while -e checks for an empty file.
upvoted 0 times
...

Save Cancel