ISTQB CTFL-Foundation Exam - Topic 3 Question 47 Discussion

Actual exam question for ISTQB's CTFL-Foundation exam

Question #: 47
Topic #: 3

A garden irrigation system allows the user to specify 2 inputs:

1. Frequency - The number of times the system should be automatically switched on per day; minimum once per day, maximum 5 times

2. Duration - The duration of operation, in whole minutes, each time it is switched on; ranging from 1 to 60

Applying 2-value boundary value analysis Which option best options has the correct test set of valid and invalid boundary values?

CFrequency 0, 1, 5, 6; Duration 0, 1, 30, 60, 61

DFrequency 0, 1, 2, 5, 6; Duration 0, 1, 30, 60, 61

BFrequency 0, 1, 5, 6; Duration 59 seconds, 1 minute, 60 minutes, 60 minutes 1 second

AFrequency 1, 5; Duration 1, 60

Show Suggested Answer

Suggested Answer: C

Boundary value analysis involves testing at the boundaries between partitions. For the Frequency input, valid boundaries are 1 and 5, while invalid boundaries are 0 and 6. For the Duration input, valid boundaries are 1 and 60 minutes, while invalid boundaries are 0 and 61 minutes. Therefore, Option C includes the correct set of valid and invalid boundary values for both inputs.

by Jeffrey at Jan 26, 2026, 02:38 AM

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Lynelle

1 day ago

This seems pretty straightforward. Just test the min and max values for both inputs, and you should be good to go. Easy peasy!

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Kristel

6 days ago

Hmm, I'd throw in a few extra test cases just to be safe. Maybe try a frequency of 0 and a duration of 61 minutes, just to see what happens. You never know!

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Ellsworth

11 days ago

Definitely need to test the boundary values, but don't forget to include some invalid values in the middle of the range too. Gotta cover all the bases!

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Adria

17 days ago

The test set should include the minimum and maximum values for both frequency and duration, as well as one value just below and one just above the valid range for each.

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Niesha

22 days ago

I’m a bit confused about how to apply the 2-value boundary analysis here. Should I just focus on the edges or include values just outside the boundaries as well?

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Ranee

27 days ago

I feel like we had a similar question where we had to identify invalid values too. Maybe something like 0 and 6 for frequency, and 0 and 61 for duration?

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Tonja

2 months ago

I think the valid boundaries would be 1 and 5 for frequency, and 1 and 60 for duration, but I might be mixing it up with another question we did.

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Rosendo

2 months ago

I remember we practiced boundary value analysis, but I'm not sure if I should include the minimum and maximum values for both inputs.

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Teri

2 months ago

This seems straightforward enough. I'll just need to be careful to double-check my work and make sure I don't miss any of the key boundary conditions.

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Minna

2 months ago

I think I've got a good handle on the boundary values now. I'll make sure to thoroughly test each of those cases to ensure I cover all the bases.

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Winfred

2 months ago

The duration input is a bit trickier. The valid range is 1 to 60 minutes, so I'll need to test 1, 30, and 60. For the invalid values, I'll try 0 and 61.

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Julieta

3 months ago

Okay, let's see. For frequency, the valid range is 1 to 5, so I'll need to test the values 1, 2, 4, and 5. For the invalid values, I'll try 0 and 6.

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Oliva

3 months ago

Hmm, this looks like a classic boundary value analysis problem. I'll need to identify the valid and invalid boundaries for both the frequency and duration inputs.

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