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ISTQB Exam ATA Topic 6 Question 30 Discussion

Actual exam question for ISTQB's ATA exam
Question #: 30
Topic #: 6
[All ATA Questions]

A route calculation for a car navigation system has been developed using the following state table:

How many test cases are needed to achieve 0-switch coverage?

[K3] 2 credits

Show Suggested Answer Hide Answer
Suggested Answer: A

Contribute your Thoughts:

Carrol
17 days ago
They should add a new state to the table: 'Driver fell asleep at the wheel'. That would really spice things up!
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Nohemi
24 days ago
I heard the navigation system was so advanced, it could even find the shortest route to the nearest mechanic. Gotta love those state tables!
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Carry
25 days ago
Ah, the joys of state tables and test case planning. I'm feeling lucky, so I'm going to go with A - 3 test cases. What could go wrong?
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Cary
3 days ago
User 1: I think the answer is B) 6
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Tequila
4 days ago
User 1: I think A) 3 test cases should be enough.
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Loreta
1 months ago
This is making my head spin! I'm going to go with D - 12 test cases. Better safe than sorry, right?
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Vicki
19 days ago
I'm not so sure, I think A - 3 test cases might be enough for 0-switch coverage.
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Loreta
29 days ago
I think you're right, D does seem like the safest option.
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Lynelle
1 months ago
Hmm, I'm not too sure about this. Let me think it through... I'll go with C - 7 test cases, just to be on the safe side.
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Marshall
2 months ago
Wow, this looks like a tricky one! I think I'll go with option B - 6 test cases. That seems like the most comprehensive coverage to me.
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Jolene
17 days ago
I think option D - 12 test cases might be needed for a more thorough coverage.
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Martina
1 months ago
I agree with you, option B - 6 test cases does seem like the best choice for achieving 0-switch coverage.
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Lashawn
2 months ago
I'm not sure, but I think the answer might be C) 7, as we need to cover all possible combinations of states.
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Victor
2 months ago
I agree with Ty, because we need to test all possible transitions between states.
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Ty
2 months ago
I think the answer is B) 6.
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