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Informatica PR000041 Exam - Topic 1 Question 31 Discussion

Actual exam question for Informatica's PR000041 exam
Question #: 31
Topic #: 1
[All PR000041 Questions]

The user creates a mapping by using aggregator transformation. The aggregator transformation receives sorted input from sorted transformation. What is the dafault partition type for aggregator transformation?

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Suggested Answer: B

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Patrick
4 months ago
Totally agree with D, it fits the logic perfectly!
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Lacey
4 months ago
Wait, is it really D? I thought it was something else!
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Jose
4 months ago
Definitely D! Makes sense with sorted input.
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Lavonda
4 months ago
I thought it was A, pass-through.
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Bobbie
5 months ago
Default partition type is D, based on transformation scope.
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Devora
5 months ago
I feel like the answer might be "based on the transformation scope," but I can't recall the specifics of why that would be the case.
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Tasia
5 months ago
I remember practicing a question about partition types, and I think the aggregator uses hash auto-keys by default, but I could be mixing it up with another transformation.
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Lettie
5 months ago
I think the default partition type for the aggregator transformation is related to how data is grouped, but I'm not entirely sure if it's pass-through or something else.
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Izetta
5 months ago
I thought the default was pass-through, but now I'm questioning if that's only for certain scenarios. I need to double-check my notes on this!
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Stanford
5 months ago
I'm a little confused on this one. I know the Scheduler is involved in Pod scheduling, but I'm not sure if it's the only component responsible for the Node assignment. Maybe the API Server or the Controller Manager also play a role? I'll have to review my notes to be sure.
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Kristin
5 months ago
I'm a bit confused by the (?:) part - is that a non-capturing group? I'll need to double-check the syntax on that.
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Demetra
5 months ago
Okay, I've got a strategy for this. I'll start by thinking through the purpose of the Shared Path Tree and the Source Path Tree, and how the switchover process works. That should help me determine the correct answer.
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