No problem, I've got this. The mode is the most frequent value, the median is the middle value, and the mean is the average. I just need to plug those into the inequalities and select the right one.
Okay, I think I've got this. I'll start by sorting the data and finding the median, then calculate the mean and mode to see which inequality holds true.
Hmm, I'm a bit unsure about how to approach this. I'll need to review my notes on measures of central tendency to make sure I'm calculating them correctly.
This looks like a straightforward statistics problem. I'll need to calculate the mode, median, and mean from the given data to determine which inequality is true.
Hmm, this is a tricky one. I'm going to have to put on my thinking cap and crunch some numbers. Wait, is that a calculator in my pocket or am I just happy to see this question?
D. Median < Mode < Mean. This makes the most sense to me based on the information provided. The mode is the most common household size, the median is the middle value, and the mean is pulled up by the larger households.
I'm not sure about this one. The distribution seems a bit complicated, but I'm leaning towards C. Median < Mean < Mode. The median should be in the middle, with the mean a bit higher and the mode being the highest.
I think the answer is B. Mode < Mean < Median. The distribution shows more households have fewer people, so the mode should be less than the mean, which should be less than the median.
Sommer
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