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IFoA Exam IFoA_CAA_M0 Topic 7 Question 89 Discussion

Actual exam question for IFoA's IFoA_CAA_M0 exam
Question #: 89
Topic #: 7
[All IFoA_CAA_M0 Questions]

A geometric series is given by

Identify the values of x for which the series converges.

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Suggested Answer: B

by Jesusa at Aug 14, 2025, 12:39 PM

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Tien
5 days ago
I’m a bit unsure, but I think I practiced a similar question where the convergence condition was based on the ratio. Could it be option B?
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Tomas
11 days ago
I remember that for a geometric series to converge, the absolute value of the common ratio must be less than 1. So, I think it might be related to x being between -1 and 1.
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Alpha
16 days ago
Wait, what? The question is asking about the values of x for which the series converges, but the options don't seem to match the typical convergence condition. I better re-read this carefully and make sure I understand it properly.
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Dalene
21 days ago
Okay, I've got this. The series converges if |x| < 1, so the answer must be B. -1 < x < 1. Time to move on to the next question!
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Ashley
26 days ago
Hmm, I remember learning about this in class, but I'm a bit fuzzy on the details. Let me think through the key properties of geometric series and see if I can figure out the correct answer.
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Isabelle
1 months ago
This looks like a straightforward question on the convergence of geometric series. I'll start by reviewing the conditions for convergence and then apply them to the given series.
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Tayna
1 months ago
I believe the correct answer is B) -1 < x < 1 because the series converges when the common ratio is between -1 and 1.
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Kelvin
3 months ago
I agree with Margot, the series converges for -1 < x < 1 because the common ratio is between -1 and 1.
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Novella
3 months ago
Hmm, this seems straightforward. The series converges when -1 < x < 1, so I'll go with option B.
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Evangelina
1 months ago
I agree, the series converges when -1 < x < 1.
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Margot
3 months ago
I think the series converges for -1 < x < 1.
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