A geometric series is given by

Identify the values of x for which the series converges.
Suggested Answer: B
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21 comments · newest first
KA
Katheryn
2 days ago
True, that would include values where it diverges.
AR
Arthur
7 days ago
What about A) -1 x 1? It seems too broad.
MA
Malika
12 days ago
I remember learning that. If |r| < 1, it converges.
OC
Ocie
17 days ago
I feel confident about that too. It’s a standard result for geometric series.
FL
Florinda
23 days ago
Yeah, I agree. The series converges in that range.
KA
Katheryn
28 days ago
I think the answer is B) -1 < x < 1.
TA
Tawny
1 month ago
C and D are way off. They include values that diverge.
FR
Francoise
1 month ago
I’m leaning towards B too. It’s the standard for geometric series.
LE
Lenny
1 month ago
Definitely B. The series diverges outside that range.
AD
Adelaide
2 months ago
I feel like A is too broad. It doesn't capture the convergence.
JE
Jeannetta
2 months ago
Agreed, B seems right. The ratio must be less than 1.
ME
Melinda
2 months ago
I think the series converges for -1 < x < 1.
FA
Farrah
2 months ago
Yup, definitely B) -1 < x < 1!
HE
Heidy
2 months ago
Just to clarify, geometric series converge when |r| < 1.
LA
Lawana
2 months ago
Wait, are you sure it’s not -5 < x < 5? Seems too broad.
AL
Alison
3 months ago
Totally agree, that's the standard range for convergence!
LO
Lorrine
3 months ago
The series converges for -1 < x < 1.
CE
Cecily
3 months ago
I feel like the answer is definitely B) -1 < x < 1, but I need to double-check the conditions for convergence.
NE
Nell
3 months ago
I'm not entirely sure about the boundaries. Could it be -5 < x < 5? That seems a bit too broad, right?
MO
Moira
3 months ago
I think we practiced a similar question where we had to find the range of x for convergence. Was it something like -1 < x < 1?
DA
Daryl
4 months ago
I remember that for a geometric series to converge, the absolute value of the common ratio must be less than 1.