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IFoA_CAA_M0 Exam - Topic 10 Question 67 Discussion

Actual exam question for IFoA's IFoA_CAA_M0 exam
Question #: 67
Topic #: 10
[All IFoA_CAA_M0 Questions]

Calculate the total area enclosed by the x-axis and the function below, between x =1.5 and x = 2.

f(x) = 2x3

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Suggested Answer: B

by Carin at Aug 06, 2024, 08:43 PM

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Amira
6 months ago
I’m surprised it’s not a whole number!
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Rodolfo
6 months ago
Totally agree, it’s around 5.469!
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Anjelica
6 months ago
Wait, how do we even calculate that?
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Suzan
7 months ago
I think it's closer to 5.469!
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Felicidad
7 months ago
The area is definitely between 2.7 and 10.9.
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Dorathy
7 months ago
I feel like the answer might be around 5 or 8, but I can’t recall the exact calculations we did in class.
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Sophia
7 months ago
I’m a bit confused about whether I need to subtract anything since the function is above the x-axis in this range.
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Wade
7 months ago
I think we did a similar problem where we had to integrate a cubic function. I hope I can remember the limits correctly!
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Lilli
8 months ago
I remember we practiced finding areas under curves, but I’m not sure if I should use definite integrals for this one.
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Leeann
8 months ago
Okay, let me think this through step-by-step. I need to integrate the function, then evaluate the integral between the given limits to find the total area. I've got this!
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Earleen
8 months ago
Wait, what? I thought we were supposed to find the area under the curve, not just integrate it. I'm a bit confused on the exact question here.
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Mica
8 months ago
Hmm, I'm a bit unsure about this one. Integrating polynomials can be tricky, and I want to make sure I set up the problem correctly.
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Lashanda
8 months ago
Okay, this looks like a straightforward integral problem. I'll need to integrate the function f(x) = 2x^3 between the limits x = 1.5 and x = 2.
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James
8 months ago
No problem, I've got this! I'll just use the power rule to integrate 2x^3 and then plug in the limits. Should be a piece of cake.
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Denny
8 months ago
This seems like a straightforward question about controlling access to a specific price book. I think the key is understanding how to use the organization-wide defaults and sharing rules effectively.
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Cordell
2 years ago
I also calculated the area and got 10.938. I think D is the correct answer.
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Kip
2 years ago
I got 10.938 as the total area. So, the answer should be D.
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Tesha
2 years ago
I agree. We can use integration to calculate it.
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Kip
2 years ago
I think we need to find the area under the curve.
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Tayna
2 years ago
I calculated it as well and got the same answer. B) 5.469 seems right.
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Linwood
2 years ago
Wait, we're supposed to do math on this test? I thought it was a hot dog eating contest. Guess I'm out of luck.
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Carla
2 years ago
2.734 seems a bit low, but hey, maybe I'm a genius and the rest of you are just numb to your calculators. I'm going with that!
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Maybelle
2 years ago
I'll go with 8.000, let's see who's right.
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Natalie
2 years ago
I'm going with 5.469, it seems more reasonable to me.
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Dona
2 years ago
I think the answer is 2.734 too.
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Howard
2 years ago
10.938? Really? That's way too high, I must have messed up somewhere. Time to brush up on my math skills.
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Kendra
2 years ago
No problem, math can be tricky sometimes. Good luck with your revision!
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Elliot
2 years ago
Yeah, I think I made a mistake in my calculations. Thanks for the reminder.
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Johanna
2 years ago
Don't worry, it happens. Just double check your calculations.
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Marla
2 years ago
D) 10.938
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Troy
2 years ago
C) 8.000
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Delisa
2 years ago
B) 5.469
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Kanisha
2 years ago
A) 2.734
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Trinidad
2 years ago
Hmm, I think it's 8.000. Can't be too hard, right? I mean, it's just some basic integration.
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Francine
2 years ago
I got 5.469, that's gotta be the right answer. Calculus is my jam!
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Dominic
2 years ago
I agree, 5.469 is the correct answer for the total area enclosed.
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Erasmo
2 years ago
Nice job! Calculus can be tricky, but you nailed it with 5.469.
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Henriette
2 years ago
I believe the correct answer is B) 5.469.
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Marshall
2 years ago
I agree. We can use integration to calculate it.
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Jovita
2 years ago
I think we need to find the area under the curve.
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