Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

IFoA_CAA_M0 Exam - Topic 10 Question 67 Discussion

Calculate the total area enclosed by the x-axis and the function below, between x =1.5 and x = 2.f(x) = 2x3
B) 5.469
A) 2.734
C) 8.000
D) 10.938

IFoA_CAA_M0 Exam - Topic 10 Question 67 Discussion

Actual exam question for IFoA's IFoA_CAA_M0 exam
Question #: 67
Topic #: 10
[All IFoA_CAA_M0 Questions]

Calculate the total area enclosed by the x-axis and the function below, between x =1.5 and x = 2.

f(x) = 2x3

Show Suggested Answer Hide Answer
Suggested Answer: B

by Carin at Aug 06, 2024, 08:43 PM

Limited Time Offer

25%

Off

Get Premium IFoA_CAA_M0 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Amira
7 months ago
I’m surprised it’s not a whole number!
upvoted 0 times
...
Rodolfo
8 months ago
Totally agree, it’s around 5.469!
upvoted 0 times
...
Anjelica
8 months ago
Wait, how do we even calculate that?
upvoted 0 times
...
Suzan
8 months ago
I think it's closer to 5.469!
upvoted 0 times
...
Felicidad
8 months ago
The area is definitely between 2.7 and 10.9.
upvoted 0 times
...
Dorathy
9 months ago
I feel like the answer might be around 5 or 8, but I can’t recall the exact calculations we did in class.
upvoted 0 times
...
Sophia
9 months ago
I’m a bit confused about whether I need to subtract anything since the function is above the x-axis in this range.
upvoted 0 times
...
Wade
9 months ago
I think we did a similar problem where we had to integrate a cubic function. I hope I can remember the limits correctly!
upvoted 0 times
...
Lilli
9 months ago
I remember we practiced finding areas under curves, but I’m not sure if I should use definite integrals for this one.
upvoted 0 times
...
Leeann
9 months ago
Okay, let me think this through step-by-step. I need to integrate the function, then evaluate the integral between the given limits to find the total area. I've got this!
upvoted 0 times
...
Earleen
9 months ago
Wait, what? I thought we were supposed to find the area under the curve, not just integrate it. I'm a bit confused on the exact question here.
upvoted 0 times
...
Mica
9 months ago
Hmm, I'm a bit unsure about this one. Integrating polynomials can be tricky, and I want to make sure I set up the problem correctly.
upvoted 0 times
...
Lashanda
9 months ago
Okay, this looks like a straightforward integral problem. I'll need to integrate the function f(x) = 2x^3 between the limits x = 1.5 and x = 2.
upvoted 0 times
...
James
9 months ago
No problem, I've got this! I'll just use the power rule to integrate 2x^3 and then plug in the limits. Should be a piece of cake.
upvoted 0 times
...
Denny
9 months ago
This seems like a straightforward question about controlling access to a specific price book. I think the key is understanding how to use the organization-wide defaults and sharing rules effectively.
upvoted 0 times
...
Cordell
2 years ago
I also calculated the area and got 10.938. I think D is the correct answer.
upvoted 0 times
...
Kip
2 years ago
I got 10.938 as the total area. So, the answer should be D.
upvoted 0 times
...
Tesha
2 years ago
I agree. We can use integration to calculate it.
upvoted 0 times
...
Kip
2 years ago
I think we need to find the area under the curve.
upvoted 0 times
...
Tayna
2 years ago
I calculated it as well and got the same answer. B) 5.469 seems right.
upvoted 0 times
...
Linwood
2 years ago
Wait, we're supposed to do math on this test? I thought it was a hot dog eating contest. Guess I'm out of luck.
upvoted 0 times
...
Carla
2 years ago
2.734 seems a bit low, but hey, maybe I'm a genius and the rest of you are just numb to your calculators. I'm going with that!
upvoted 0 times
Maybelle
2 years ago
I'll go with 8.000, let's see who's right.
upvoted 0 times
...
Natalie
2 years ago
I'm going with 5.469, it seems more reasonable to me.
upvoted 0 times
...
Dona
2 years ago
I think the answer is 2.734 too.
upvoted 0 times
...
...
Howard
2 years ago
10.938? Really? That's way too high, I must have messed up somewhere. Time to brush up on my math skills.
upvoted 0 times
Kendra
2 years ago
No problem, math can be tricky sometimes. Good luck with your revision!
upvoted 0 times
...
Elliot
2 years ago
Yeah, I think I made a mistake in my calculations. Thanks for the reminder.
upvoted 0 times
...
Johanna
2 years ago
Don't worry, it happens. Just double check your calculations.
upvoted 0 times
...
Marla
2 years ago
D) 10.938
upvoted 0 times
...
Troy
2 years ago
C) 8.000
upvoted 0 times
...
Delisa
2 years ago
B) 5.469
upvoted 0 times
...
Kanisha
2 years ago
A) 2.734
upvoted 0 times
...
...
Trinidad
2 years ago
Hmm, I think it's 8.000. Can't be too hard, right? I mean, it's just some basic integration.
upvoted 0 times
...
Francine
2 years ago
I got 5.469, that's gotta be the right answer. Calculus is my jam!
upvoted 0 times
Dominic
2 years ago
I agree, 5.469 is the correct answer for the total area enclosed.
upvoted 0 times
...
Erasmo
2 years ago
Nice job! Calculus can be tricky, but you nailed it with 5.469.
upvoted 0 times
...
...
Henriette
2 years ago
I believe the correct answer is B) 5.469.
upvoted 0 times
...
Marshall
2 years ago
I agree. We can use integration to calculate it.
upvoted 0 times
...
Jovita
2 years ago
I think we need to find the area under the curve.
upvoted 0 times
...

Save Cancel