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Calculate the total area enclosed by the x-axis and the function below, between x =1.5 and x = 2.
f(x) = 2x3
Suggested Answer: B
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40 comments · newest first
AM
Amira
10 months ago
I’m surprised it’s not a whole number!
RO
Rodolfo
11 months ago
Totally agree, it’s around 5.469!
AN
Anjelica
11 months ago
Wait, how do we even calculate that?
SU
Suzan
11 months ago
I think it's closer to 5.469!
FE
Felicidad
11 months ago
The area is definitely between 2.7 and 10.9.
DO
Dorathy
12 months ago
I feel like the answer might be around 5 or 8, but I can’t recall the exact calculations we did in class.
SO
Sophia
12 months ago
I’m a bit confused about whether I need to subtract anything since the function is above the x-axis in this range.
WA
Wade
12 months ago
I think we did a similar problem where we had to integrate a cubic function. I hope I can remember the limits correctly!
LI
Lilli
1 year ago
I remember we practiced finding areas under curves, but I’m not sure if I should use definite integrals for this one.
LE
Leeann
1 year ago
Okay, let me think this through step-by-step. I need to integrate the function, then evaluate the integral between the given limits to find the total area. I've got this!
EA
Earleen
1 year ago
Wait, what? I thought we were supposed to find the area under the curve, not just integrate it. I'm a bit confused on the exact question here.
MI
Mica
1 year ago
Hmm, I'm a bit unsure about this one. Integrating polynomials can be tricky, and I want to make sure I set up the problem correctly.
LA
Lashanda
1 year ago
Okay, this looks like a straightforward integral problem. I'll need to integrate the function f(x) = 2x^3 between the limits x = 1.5 and x = 2.
JA
James
1 year ago
No problem, I've got this! I'll just use the power rule to integrate 2x^3 and then plug in the limits. Should be a piece of cake.
DE
Denny
1 year ago
This seems like a straightforward question about controlling access to a specific price book. I think the key is understanding how to use the organization-wide defaults and sharing rules effectively.
CO
Cordell
2 years ago
I also calculated the area and got 10.938. I think D is the correct answer.
KI
Kip
2 years ago
I got 10.938 as the total area. So, the answer should be D.
TE
Tesha
2 years ago
I agree. We can use integration to calculate it.
KI
Kip
2 years ago
I think we need to find the area under the curve.
TA
Tayna
2 years ago
I calculated it as well and got the same answer. B) 5.469 seems right.
LI
Linwood
2 years ago
Wait, we're supposed to do math on this test? I thought it was a hot dog eating contest. Guess I'm out of luck.
CA
Carla
2 years ago
2.734 seems a bit low, but hey, maybe I'm a genius and the rest of you are just numb to your calculators. I'm going with that!
MA
Maybelle
2 years ago
I'll go with 8.000, let's see who's right.
NA
Natalie
2 years ago
I'm going with 5.469, it seems more reasonable to me.
DO
Dona
2 years ago
I think the answer is 2.734 too.
HO
Howard
2 years ago
10.938? Really? That's way too high, I must have messed up somewhere. Time to brush up on my math skills.
KE
Kendra
2 years ago
No problem, math can be tricky sometimes. Good luck with your revision!
EL
Elliot
2 years ago
Yeah, I think I made a mistake in my calculations. Thanks for the reminder.
JO
Johanna
2 years ago
Don't worry, it happens. Just double check your calculations.
MA
Marla
2 years ago
D) 10.938
TR
Troy
2 years ago
C) 8.000
DE
Delisa
2 years ago
B) 5.469
KA
Kanisha
2 years ago
A) 2.734
TR
Trinidad
2 years ago
Hmm, I think it's 8.000. Can't be too hard, right? I mean, it's just some basic integration.
FR
Francine
2 years ago
I got 5.469, that's gotta be the right answer. Calculus is my jam!
DO
Dominic
2 years ago
I agree, 5.469 is the correct answer for the total area enclosed.
ER
Erasmo
2 years ago
Nice job! Calculus can be tricky, but you nailed it with 5.469.
HE
Henriette
2 years ago
I believe the correct answer is B) 5.469.
MA
Marshall
2 years ago
I agree. We can use integration to calculate it.
JO
Jovita
2 years ago
I think we need to find the area under the curve.