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IFoA_CAA_M0 Exam - Topic 10 Question 38 Discussion

Actual exam question for IFoA's IFoA_CAA_M0 exam
Question #: 38
Topic #: 10
[All IFoA_CAA_M0 Questions]

A coin is tossed 7 times.

Calculate the number of possible combinations that gives 4 heads and 3 tails.

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Suggested Answer: A

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Annmarie
4 months ago
35 makes sense, good job!
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Mitsue
4 months ago
I thought it would be way higher than that!
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Chaya
4 months ago
Wait, are you sure it's not 42?
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Isadora
4 months ago
Totally agree, it's 35!
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Kyoko
5 months ago
The answer is 35 combinations!
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Lynelle
5 months ago
I’m pretty confident it’s 210 because I remember the formula involves factorials, but I should double-check my notes.
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Maurine
5 months ago
I feel like I might have confused the combinations with permutations in my studies. Is it really just 7 choose 4?
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Daron
5 months ago
I think we need to use the combination formula for this, but I'm not entirely sure how to set it up.
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Lashon
5 months ago
I remember practicing similar questions, and I think the answer is 35, but I can't recall the exact calculation.
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Elli
5 months ago
Hmm, I'm not totally sure about this one. I know continuous reinforcement is good for quickly establishing a behavior, but I think intermittent might be better for maintaining it over time. Let me think this through a bit more.
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Zena
5 months ago
Lists and Data Extensions seems like the safest bet to me. That way I can cover both options and not risk missing something important.
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