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Huawei Exam H35-560 Topic 1 Question 43 Discussion

Actual exam question for Huawei's H35-560 exam
Question #: 43
Topic #: 1
[All H35-560 Questions]

Which of the following is the correct description of the following LTE neighboring cell planning? (Multiple choice)

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Suggested Answer: B

Contribute your Thoughts:

Deandrea
5 days ago
Alright folks, no need to get too 'neighborly' here. Just focus on the technical aspects and you'll do great!
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Curt
7 days ago
A is way too simple. Geographically related neighboring cells? Come on, we need a more comprehensive answer than that for an LTE exam question.
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Millie
10 days ago
D is the funniest answer. Expecting the ANR function to completely replace the need for initial network neighborhood planning is just hilarious!
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Bettina
27 days ago
C seems to make the most sense. The LTE neighboring area detection cycle is short, so we only need to focus on not missing neighbors, not strictly sorting them by signal strength.
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Chantell
19 hours ago
But what about option D? ANR function can completely replace the initial network neighborhood planning.
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Celeste
3 days ago
I agree, C does seem like the most logical choice.
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Rory
29 days ago
But C makes more sense because of the short detection cycle.
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Carlee
30 days ago
I disagree, I believe it's A.
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Rory
1 months ago
I think the correct description is C.
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Colton
1 months ago
I think B is the correct answer. The distance between stations in dense urban and ordinary urban areas is relatively close, so more neighboring cells should be considered.
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Daniel
13 days ago
I agree, in dense urban areas, having more neighboring cells at a closer distance is important for LTE network planning.
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Lucia
14 days ago
I think B is the correct answer. The distance between stations in dense urban and ordinary urban areas is relatively close, so more neighboring cells should be considered.
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Idella
1 months ago
But C makes more sense because of the short detection cycle.
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Janae
1 months ago
I disagree, I believe it's A.
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Idella
1 months ago
I think the correct description is C.
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a