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Huawei H35-210_V2.5 Exam - Topic 1 Question 31 Discussion

In GPON network, which of the following reasons may cause ONU to fail to go online?
A) The optical power received by the ONU is greater than the overload optical power. and B) The optical power received by the ONU is less than the sensitivity value and C) There is abnormal attenuation on the ODN line. and D) The ODN line is too long and exceeds the online distance set by the system.

Huawei H35-210_V2.5 Exam - Topic 1 Question 31 Discussion

Actual exam question for Huawei's H35-210_V2.5 exam
Question #: 31
Topic #: 1
[All H35-210_V2.5 Questions]

In GPON network, which of the following reasons may cause ONU to fail to go online?

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Suggested Answer: A, B, C, D

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Bok
7 months ago
I disagree with A, it’s not a common reason for failure.
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Lasandra
7 months ago
Wait, A? I thought too much power would just cause issues, not prevent it from going online.
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Hoa
8 months ago
C is also a possibility, abnormal attenuation can cause problems.
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Shelia
8 months ago
I think D is a big issue too, long lines can mess things up.
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Yong
8 months ago
Definitely B, if the power is too low, the ONU won't connect.
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Carmelina
8 months ago
I vaguely recall that abnormal attenuation could definitely affect the signal quality, so option C might be a valid reason for the ONU failing to connect.
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Kristeen
8 months ago
I think option B makes sense because if the optical power is below the sensitivity threshold, the ONU won't work. That sounds familiar from our practice questions.
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Tegan
8 months ago
I remember something about optical power levels, but I'm not sure if overload power can actually prevent the ONU from going online.
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Azzie
8 months ago
I’m a bit confused about the distance limits. I know the ODN line length matters, but I can't remember if it’s specifically mentioned in the study materials.
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Staci
9 months ago
Hmm, I'm a bit unsure about the differences between NetApp Storage Encryption (NSE) and NetApp Volume Encryption (NVE). I'll need to review those details carefully.
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Thersa
9 months ago
Ah, I see now - the partitioning is based on the cell_id column, with each partition covering a range of values. This should be a pretty straightforward question to answer.
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