Erasure code redundancy technology used in Huawei OceanStor 9000 supports higher reliability and more flexible redundancy than traditional RAID algorithms.
Which of the following statements regarding the principle of Erasure code N + M is wong?
I remember studying that N + M means you have N data blocks and M parity blocks, but I'm not sure if the statement about re-Erasure Code storage mode is correct.
Hmm, the Erasure code technology is supposed to provide higher reliability and more flexible redundancy than traditional RAID. I think I have a good understanding of how it works, so I'm feeling confident about this one.
I'm a bit confused by the wording of the question. Is it asking which statement is incorrect, or which one is correct? I want to make sure I don't accidentally select the wrong answer.
Okay, let me think this through. The question is asking which statement about the Erasure code N + M principle is wrong, so I need to carefully analyze each option.
The key thing to remember is that Erasure code N + M involves writing data into N data blocks and calculating M check blocks. I'll need to double-check the details of each option to identify the one that's incorrect.
Alright, let's focus here. The key is understanding the principle of Erasure code N+M. I think the correct answer is D, since the system should support up to N hard disk failures, not just M.
Haha, 'wong'? I think the person who wrote this question needs to brush up on their English. Maybe they're trying to be funny, but it's a bit cringeworthy.
Okay, let me think this through. If the system stores N+M data blocks in parallel, then it should be able to tolerate up to M disk failures, not just N. That must be the 'wong' statement.
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