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Huawei Exam H12-821_V1.0 Topic 1 Question 39 Discussion

Actual exam question for Huawei's H12-821_V1.0 exam
Question #: 39
Topic #: 1
[All H12-821_V1.0 Questions]

A non-client is an IBGP peer that functions as neither an RR nor a client. A non-client must establish fully meshed connections with the RR and all the other non-clients.

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Suggested Answer: A

Contribute your Thoughts:

Cory
26 days ago
B) FALSE. No way am I letting my non-clients slack off. They better be fully meshed and ready to party with the RR!
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Janella
27 days ago
Well, at least it's not as complicated as trying to remember all the OSPF area types. One less headache, I guess.
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Salome
1 months ago
Ah, the joys of IBGP topology - where every non-client must be BFFs with the RR and each other. No slacking allowed!
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Isadora
23 hours ago
B) FALSE
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Eva
11 days ago
That's right, every non-client must have fully meshed connections with the RR and other non-clients.
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Lauryn
15 days ago
A) TRUE
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Carlee
1 months ago
I knew it! Fully meshed connections, no shortcuts allowed in the world of IBGP.
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Starr
24 hours ago
B) FALSE
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Bonita
8 days ago
That's right, no shortcuts in IBGP!
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Tyra
12 days ago
B) FALSE
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Florinda
14 days ago
That's right, no shortcuts in IBGP!
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Lajuana
28 days ago
A) TRUE
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An
1 months ago
A) TRUE
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Yvonne
2 months ago
A) TRUE because a non-client in IBGP must establish fully meshed connections with the RR and all other non-clients, so it functions as neither an RR nor a client.
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Malinda
2 months ago
B) FALSE
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Aimee
2 months ago
A) TRUE
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