Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

Huawei H12-311_V3.0 Exam - Topic 1 Question 15 Discussion

Which of the following is correct about the power calculation ()?(Select 3 Answers)
A) 0 dBm = 1 mW and B) 3 dBm = 2 mW and D) 27 dBm = 500mW
C) 10 dBm = 100mW

Huawei H12-311_V3.0 Exam - Topic 1 Question 15 Discussion

Actual exam question for Huawei's H12-311_V3.0 exam
Question #: 15
Topic #: 1
[All H12-311_V3.0 Questions]

Which of the following is correct about the power calculation ()?

(Select 3 Answers)

Show Suggested Answer Hide Answer
Suggested Answer: A, B, D

by Mari at May 04, 2022, 09:12 AM

Limited Time Offer

25%

Off

Get Premium H12-311_V3.0 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Brianne
9 months ago
Yup, all three A, B, and C are correct!
upvoted 0 times
...
Alyce
9 months ago
Wait, is D really right? 27 dBm seems off to me.
upvoted 0 times
...
Sunshine
9 months ago
C is spot on too, 10 dBm is 100 mW!
upvoted 0 times
...
Edelmira
9 months ago
I agree, B is also right, 3 dBm equals 2 mW.
upvoted 0 times
...
Lizette
10 months ago
A is definitely correct, 0 dBm is 1 mW.
upvoted 0 times
...
Sue
10 months ago
I have a vague memory that 27 dBm is not 500 mW, but I can't recall the exact value.
upvoted 0 times
...
Oneida
10 months ago
I practiced a similar question, and I think 10 dBm equals 100 mW, so C should be one of the answers.
upvoted 0 times
...
Beatriz
10 months ago
I remember that 0 dBm is definitely 1 mW, so I think A is correct.
upvoted 0 times
...
Casandra
10 months ago
I'm not entirely sure about 3 dBm, but I feel like it might be around 2 mW.
upvoted 0 times
...
Lang
10 months ago
Okay, I remember learning about this in class. The key is understanding who is responsible for the initial information classification assignments.
upvoted 0 times
...
Lashunda
10 months ago
I'm feeling pretty confident about this one. Based on the code snippet and the options, I think the answer is B. That looks like the correct way to set up an event listener and start the server.
upvoted 0 times
...

Save Cancel