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Huawei Exam H12-211 Topic 10 Question 93 Discussion

Actual exam question for Huawei's H12-211 exam
Question #: 93
Topic #: 10
[All H12-211 Questions]

The following commands output is displayd on an STP port on a swith. Which of the following statements is false?

display stp interface GigabitEthernet 0/0/1

-------[CIST Global Info][Mode STP]------- CIST Bridge :32768.4c1f-cc93-3356

Config Times :Hello 4s MaxAge 20s FwDly 15s MaxHop 20

Active Times :Hello 2s MaxAge 20s FwDly 15s MaxHop 20 CIST Root/ERPC :0 .4c1f-cc7f-3216 / 0

CIST RegRoot/IRPC :32768.4c1f-cc93-3356 / 0The interval at which the port sends configuration BPDUs is 2 seconds

Show Suggested Answer Hide Answer
Suggested Answer: A, B

by Lenny at Jul 18, 2024, 01:17 PM

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Corinne
1 years ago
The answer is clearly C. Blocking the traffic on the incoming interface is the way to go.
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Susana
11 months ago
No, I believe it's C. Blocking the traffic on the incoming interface is the correct way to prevent communication.
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Roslyn
12 months ago
I think the answer is A. Denying the traffic on the outbound ACL should prevent communication.
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Jacquelyne
1 years ago
C is the way to go. Applying the ACL on the incoming interface is the way to go.
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Milly
12 months ago
C) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter inbound acl 2000
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Louisa
1 years ago
B) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/2 traffic-filter inbound acl 2000
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Quinn
1 years ago
A) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter outbound acl 2000
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Merilyn
1 years ago
Haha, looks like the network admin is trying to keep the hosts from talking to each other. Good luck with that!
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Tanesha
11 months ago
Haha, the network admin is definitely trying to keep those hosts from communicating!
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Chanel
11 months ago
C) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter inbound acl 2000
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Yolando
11 months ago
B) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/2 traffic-filter inbound acl 2000
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Ashton
12 months ago
A) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter outbound acl 2000
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Skye
1 years ago
I think B is the answer. The ACL applied on the outgoing interface should block the traffic.
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Omega
1 years ago
The correct answer is C. The ACL applied on the incoming interface of the router will prevent communication between the hosts.
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Geoffrey
11 months ago
C) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter inbound acl 2000
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Caprice
12 months ago
B) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/2 traffic-filter inbound acl 2000
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Jeannetta
1 years ago
A) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter outbound acl 2000
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Edward
1 years ago
C) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter inbound acl 2000
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Ruth
1 years ago
B) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/2 traffic-filter inbound acl 2000
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Elmira
1 years ago
A) acl number 2000 rule 5 deny source 100.0.12.0 0.0.0.255 # interface G0/0/1 traffic-filter outbound acl 2000
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Meghann
1 years ago
I'm not sure, but I think option C might also work to prevent communication between the hosts.
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Nobuko
1 years ago
I disagree, I believe option B is the correct choice because it denies the source IP address.
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Derick
1 years ago
I think option A can prevent communication between Host A and Host B.
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