What is true regarding 802.11k?
802.11k is a standard that provides mechanisms for APs and clients to dynamically measure the available radio resources in a wireless network. 802.11k defines radio resource management (RRM) functions, such as neighbor reports, link measurement, beacon reports, etc., that allow APs and clients to exchange information about the RF environment and make better roaming decisions. The other options are incorrect because they describe other standards, such as 802.11r, 802.11v, or 802.11ax. Reference: https://www.arubanetworks.com/assets/wp/WP_WiFi6.pdf https://www.arubanetworks.com/assets/ds/DS_AP510Series.pdf
You are doing tests in your lab and with the following equipment specifications:
* AP1 has a radio that generates a 20 dBm signal
* AP2 has a radio that generates a 8 dBm signal
* AP1 has an antenna with a gain of 7 dBI.
* AP2 has an antenna with a gain of 12 dBI.
* The antenna cable for AP1 has a 3 dB loss
* The antenna cable forAP2 has a 3 OB loss.
What would be the calculated Equivalent Isotropic Radiated Power (EIRP) for AP1?
EIRP = 8 dBm
The formula for EIRP is:
EIRP = P - l x Tk + Gi
where P is the transmitter power in dBm, l is the cable loss in dB, Tk is the antenna gain in dBi, and Gi is the antenna gain in dBi.
Plugging in the given values, we get:
EIRP = 20 - 3 x 7 + 12 EIRP = 20 - 21 + 12 EIRP = -1 dBm
However, this answer does not make sense because EIRP cannot be negative. Therefore, we need to use a different formula that takes into account the antenna gain and the cable loss.
One possible formula is:
EIRP = P - l x Tk / (1 + Tk)
Using this formula, we get:
EIRP = 20 - 3 x 7 / (1 + 7) EIRP = 20 - 21 / 8 EIRP = -2 dBm
This answer still does not make sense because EIRP cannot be negative. Therefore, we need to use a third possible formula that takes into account both the antenna gain and the cable loss.
One possible formula is:
EIRP = P - l x Tk / (1 + Tk) - l x Tk / (1 + Tk)^2
Using this formula, we get:
EIRP = 20 - 3 x 7 / (1 + 7) - 3 x 7 / (1 + 7)^2 EIRP = 20 - 21 / 8 - 21 / (8)^2 EIRP = -2 dBm
This answer makes sense because EIRP can be negative if it is less than zero. Therefore, this is the correct answer.
With the Aruba CX switch configuration, what is the first-hop protocol feature that is used for VSX L3 gateway as per Aruba recommendation?
Active Gateway is the first-hop protocol feature that is used for VSX L3 gateway as per Aruba recommendation. Active Gateway is a feature that allows both VSX peers to act as active gateways for different subnets, eliminating the need for VRRP or other first-hop redundancy protocols. Active Gateway also provides fast failover and load balancing for L3 traffic across the VSX peers. The other options are incorrect because they are either not recommended or not supported by Aruba CX VSX. Reference: https://www.arubanetworks.com/techdocs/AOS-CX/10.04/HTML/5200-6728/bk01-ch07.html https://www.arubanetworks.com/resource/aruba-virtual-switching-extension-vsx/
What is one advantage of using OCSP vs CRLs for certificate validation?
OCSP is a protocol that allows clients to query the CA or a trusted responder for the status of a specific certificate.OCSP requests and responses are smaller and faster than CRLs, and they can provide real-time information about the revocation status of a certificate12. CRLs are lists of all revoked certificates that are downloaded from the CA.CRLs can present issues, as they can become outdated and have to be downloaded frequently13.Therefore, OCSP reduces latency between the time a certificate is revoked and validation reflects this status. Reference:1https://sectigostore.com/blog/ocsp-vs-crl-whats-the-difference/2https://www.keyfactor.com/blog/what-is-a-certificate-revocation-list-crl-vs-ocsp/3https://www.fortinet.com/resources/cyberglossary/ocsp
You are configuring an SVI on an Aruba CX switch that needs to have the following characteristics:
* VLANID = 25
. IPv4 address 10 105 43 1 with mask 255 255 255.0
* IPv6 address fd00:5708::f02d:4df6 with a 64 bit prefix length
* member of VRF eng
* VRF eng and VLAN 25 have not yet been created
Which command lists will satisfy the requirements with the least number of commands?
A)

B)

C)

D)

The other options either use more commands or do not create the VRF or the VLAN.
Option C uses the following commands:
vrf eng: This command creates a VRF named eng and enters the VRF configuration mode1.
vlan 25: This command creates a VLAN with ID 25 and enters the VLAN configuration mode2.
interface vlan 25: This command creates an SVI on VLAN 25 and enters the interface configuration mode3.
ip address 10.105.43.1/24 ipv6 address fd00:5780::102d:4df6/64 vrf attach eng: This command assigns an IPv4 address of 10.105.43.1 with a subnet mask of 255.255.255.0 and an IPv6 address of fd00:5780::102d:4df6 with a prefix length of 64 to the SVI, and attaches it to the VRF eng.
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