HPE3-U01 Exam - Topic 6 Question 64 Discussion

Actual exam question for HP's HPE3-U01 exam

Question #: 64
Topic #: 6

[All HPE3-U01 Questions]

How many IP assignable addresses are contained in 10.0.128.0/23?

A4094

B254

C510

D512

Show Suggested Answer

Suggested Answer: D

by Maurine at Jul 12, 2025, 09:20 AM

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India

7 months ago

Nope, definitely 510. The subnet mask tells you that.

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Dudley

7 months ago

Totally agree, 510 is the right answer!

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Chuck

7 months ago

It's 510 assignable addresses in that range.

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Rickie

8 months ago

Wait, are you sure? I thought it was more like 512.

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Patrick

8 months ago

Wow, I didn't know it was that specific!

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Gilma

8 months ago

I thought it was 4094 for a /23, but now I’m questioning that. I need to double-check how the subnetting works.

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Alida

8 months ago

I’m a bit confused about the math here. Is it 512 total addresses minus 2 for the network and broadcast? That would leave 510, right?

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Stephaine

9 months ago

I practiced a similar question last week, and I think it was about calculating usable addresses. I believe you subtract 2 for the network and broadcast addresses.

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An

9 months ago

I think I remember that a /23 subnet has 9 bits for hosts, which might mean 2^9 addresses, but I’m not sure how many are usable.

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Paz

9 months ago

The key is understanding how the /23 subnet mask works. It gives you 9 host bits, so the total number of assignable addresses is 2^9 - 2 = 510.

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Reena

9 months ago

I'm a bit confused on how to approach this. Let me re-read the question and think it through step-by-step.

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Slyvia

9 months ago

Wait, isn't it 2^8 - 2 = 254 addresses? The /23 subnet only uses 23 bits, so the last 8 bits are for the hosts.

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Marica

10 months ago

Okay, I've got this. The /23 subnet mask means 23 bits for the network and 9 bits for the host. That's 2^9 - 2 = 510 assignable addresses.

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Portia

10 months ago

Hmm, this looks like a tricky IP addressing question. I'll need to think through the subnet mask and network range carefully.

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Christiane

11 months ago

As a network admin, I can tell you that 10.0.128.0/23 is the way to go. D is the correct choice, hands down.

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Karma

11 months ago

Wait, is this a trick question? What if the answer is actually 42? *laughs* Nah, I'm sticking with D.

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Donte

10 months ago

I'm going with B) 254.

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Frank

10 months ago

I think the answer is A) 4094.

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Alise

11 months ago

I'm torn between B and C, but I'll go with C. Gotta love those subnets!

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Bulah

10 months ago

User 2: I'm torn between B and C, but I'll go with C. Gotta love those subnets!

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Valentin

10 months ago

User 1: I think the answer is B) 254.

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Fallon

12 months ago

I agree with Hillary, the correct answer is C) 510.

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German

12 months ago

Definitely D. 512 IP addresses, easy peasy!

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Matilda

10 months ago

No, it's actually D) 512

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Marsha

10 months ago

Actually, it is D) 512 IP addresses. You were right!

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Andrew

10 months ago

No way, it's definitely D) 512 IP addresses.

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Anika

11 months ago

I think it's A) 4094

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Norah

12 months ago

I think it's actually A) 4094 IP addresses.

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Hillary

12 months ago

But the subnet mask /23 gives us 2^9 - 2 = 510 usable addresses.

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Ettie

12 months ago

I believe it's C) 510.

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Hillary

1 year ago

I think the answer is A) 4094.

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Shalon

1 year ago

Hmm, let's see... 10.0.128.0/23 covers a range of 510 IP addresses? I think I'm going with C on this one.

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Malcom

11 months ago

Yes, I agree. C) 510 seems to be the correct answer.

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Fernanda

12 months ago

I think you're right, it should be 510 IP addresses.

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