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HPE3-U01 Exam - Topic 6 Question 64 Discussion
HPE3-U01 Exam - Topic 6 Question 64 Discussion
Actual exam question for HP's HPE3-U01 exam
Question #: 64
Topic #: 6
[All HPE3-U01 Questions]
How many IP assignable addresses are contained in 10.0.128.0/23?
A
4094
B
254
C
510
D
512
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Suggested Answer:
D
by
Maurine
at
Jul 12, 2025, 09:20 AM
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India
2 months ago
Nope, definitely 510. The subnet mask tells you that.
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Dudley
2 months ago
Totally agree, 510 is the right answer!
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Chuck
2 months ago
It's 510 assignable addresses in that range.
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Rickie
3 months ago
Wait, are you sure? I thought it was more like 512.
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Patrick
3 months ago
Wow, I didn't know it was that specific!
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Gilma
3 months ago
I thought it was 4094 for a /23, but now I’m questioning that. I need to double-check how the subnetting works.
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Alida
3 months ago
I’m a bit confused about the math here. Is it 512 total addresses minus 2 for the network and broadcast? That would leave 510, right?
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Stephaine
4 months ago
I practiced a similar question last week, and I think it was about calculating usable addresses. I believe you subtract 2 for the network and broadcast addresses.
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An
4 months ago
I think I remember that a /23 subnet has 9 bits for hosts, which might mean 2^9 addresses, but I’m not sure how many are usable.
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Paz
4 months ago
The key is understanding how the /23 subnet mask works. It gives you 9 host bits, so the total number of assignable addresses is 2^9 - 2 = 510.
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Reena
4 months ago
I'm a bit confused on how to approach this. Let me re-read the question and think it through step-by-step.
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Slyvia
4 months ago
Wait, isn't it 2^8 - 2 = 254 addresses? The /23 subnet only uses 23 bits, so the last 8 bits are for the hosts.
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Marica
5 months ago
Okay, I've got this. The /23 subnet mask means 23 bits for the network and 9 bits for the host. That's 2^9 - 2 = 510 assignable addresses.
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Portia
5 months ago
Hmm, this looks like a tricky IP addressing question. I'll need to think through the subnet mask and network range carefully.
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Christiane
6 months ago
As a network admin, I can tell you that 10.0.128.0/23 is the way to go. D is the correct choice, hands down.
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Karma
6 months ago
Wait, is this a trick question? What if the answer is actually 42? *laughs* Nah, I'm sticking with D.
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Donte
5 months ago
I'm going with B) 254.
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Frank
5 months ago
I think the answer is A) 4094.
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Alise
6 months ago
I'm torn between B and C, but I'll go with C. Gotta love those subnets!
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Bulah
5 months ago
User 2: I'm torn between B and C, but I'll go with C. Gotta love those subnets!
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Valentin
5 months ago
User 1: I think the answer is B) 254.
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Fallon
7 months ago
I agree with Hillary, the correct answer is C) 510.
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German
7 months ago
Definitely D. 512 IP addresses, easy peasy!
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Matilda
5 months ago
No, it's actually D) 512
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Marsha
5 months ago
Actually, it is D) 512 IP addresses. You were right!
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Andrew
5 months ago
No way, it's definitely D) 512 IP addresses.
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Anika
6 months ago
I think it's A) 4094
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Norah
7 months ago
I think it's actually A) 4094 IP addresses.
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Hillary
7 months ago
But the subnet mask /23 gives us 2^9 - 2 = 510 usable addresses.
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Ettie
7 months ago
I believe it's C) 510.
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Hillary
7 months ago
I think the answer is A) 4094.
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Shalon
7 months ago
Hmm, let's see... 10.0.128.0/23 covers a range of 510 IP addresses? I think I'm going with C on this one.
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Malcom
6 months ago
Yes, I agree. C) 510 seems to be the correct answer.
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Fernanda
7 months ago
I think you're right, it should be 510 IP addresses.
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India
2 months agoDudley
2 months agoChuck
2 months agoRickie
3 months agoPatrick
3 months agoGilma
3 months agoAlida
3 months agoStephaine
4 months agoAn
4 months agoPaz
4 months agoReena
4 months agoSlyvia
4 months agoMarica
5 months agoPortia
5 months agoChristiane
6 months agoKarma
6 months agoDonte
5 months agoFrank
5 months agoAlise
6 months agoBulah
5 months agoValentin
5 months agoFallon
7 months agoGerman
7 months agoMatilda
5 months agoMarsha
5 months agoAndrew
5 months agoAnika
6 months agoNorah
7 months agoHillary
7 months agoEttie
7 months agoHillary
7 months agoShalon
7 months agoMalcom
6 months agoFernanda
7 months ago