HP Exam HPE3-U01 Topic 2 Question 54 Discussion

Actual exam question for HP's HPE3-U01 exam

Question #: 54
Topic #: 2

[All HPE3-U01 Questions]

Given the 172.16.0.0 255.255.255.0 IP segment, how many IP addresses can be assigned to host and network devices?

A126

C128

Show Suggested Answer

Suggested Answer: A

by Abel at Dec 04, 2024, 01:28 PM

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Jodi

23 days ago

I'm just hoping the answer isn't E) 42. That would be way too cosmic for a networking exam!

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Carlota

28 days ago

I'm with Jeannetta on this one. A) 126 has got to be the correct answer. Who would waste two IP addresses for the network and broadcast addresses? Silly question.

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Jaime

29 days ago

Woah, this is a tricky one. Let me think... B) 6 seems way too low, and D) 4 just doesn't make sense. I'm going with C) 128, it feels right.

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Anastacia

4 days ago

I think C) 128 is the correct answer.

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Jeannetta

1 months ago

I'm not so sure about that. Doesn't the network address and broadcast address take up two of those addresses? I'm leaning towards A) 126.

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Ligia

18 days ago

Great, glad we figured that out together!

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Mona

26 days ago

I agree, the correct answer is A) 126.

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Earlean

1 months ago

So that leaves us with 126 usable IP addresses for host and network devices.

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Ashton

1 months ago

I think you're right, the network and broadcast addresses do take up two of the addresses.

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Remona

2 months ago

Hmm, I think the answer is C) 128. That's the number of available host addresses in a /24 subnet, right?

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Janessa

2 months ago

So that leaves us with 254 usable IP addresses for host devices. The answer should be C) 128.

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Isabella

2 months ago

I agree with Tuyet. With a /24 subnet mask, there are 256 total IP addresses, but 2 are reserved for network and broadcast addresses.

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Tuyet

2 months ago

I think the answer is C) 128.

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