I got this! The subnet mask 255.255.252.0 means the last 2 bits are available for host addresses. That gives us 2^2 = 4 subnets, and each subnet has 2^6 = 64 addresses. So the total number of addresses is 4 * 64 = 8192. Easy peasy!
Okay, let's see. The subnet mask 255.255.252.0 means we have 2 bits available in the last octet, so that should give us 2^2 = 4 subnets. I think the answer is 8192, but I'll double-check my work.
Hmm, I'm a bit unsure about this one. I know subnet masks are important, but I'm not totally confident in my ability to work through these types of problems quickly. I'll need to think it through carefully.
I think Cisco CloudLock is the best option here since it provides visibility and protection against data exfiltration, which are the key requirements mentioned in the question.
Hmm, I'm a little unsure about the details here. I know switches are better than hubs, but I'll need to carefully review the options to make sure I select the right benefits.
Erick
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