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How many experimental runs exist in a Full Factorial and fully randomized design for 5 factors with 2 replicates for the Corner Points and no Center Points? The factors in the experiment are only at 2-levels.
Suggested Answer: D
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19 comments · newest first
MA
Madalyn
24 days ago
Same here, pressure's on!
TH
Thaddeus
29 days ago
I just hope I get it right!
RH
Rhea
1 month ago
I feel like I might overthink it.
MA
Madalyn
1 month ago
Right, but I still think 128 is too low.
RH
Rhea
1 month ago
But don't forget the corner points!
TH
Thaddeus
2 months ago
2^5 factors, then times 2 for replicates.
MA
Madalyn
2 months ago
Why C)?
TH
Thaddeus
2 months ago
No way, it's C) 256 for sure.
RH
Rhea
2 months ago
I think it's B) 128.
MA
Madalyn
2 months ago
This question is tricky!
YU
Yuette
3 months ago
Not sure about that, feels like it should be less.
HA
Hana
3 months ago
Totally with you, Sanda!
HO
Hollis
3 months ago
Wait, 256? That seems high!
SA
Sanda
3 months ago
I think it’s 256 runs, right?
AD
Adolph
3 months ago
There are 32 runs for 5 factors at 2 levels, with 2 replicates.
SH
Sharen
3 months ago
I’m confused about the corner points and how they affect the total. I thought we just multiply the basic runs by the number of replicates, but now I’m not so sure.
EU
Eun
4 months ago
I practiced a similar question recently, and I think it was about 4 factors with 2 levels. If I recall correctly, it was 16 runs for that one, so maybe this one is 32 runs before considering the replicates?
TO
Tomoko
4 months ago
I'm not entirely sure, but I feel like we also need to consider the replicates. If we have 2 replicates, wouldn't that double the number of runs?
MA
Marsha
4 months ago
I think I remember that for a full factorial design, you calculate the number of runs as 2^k, where k is the number of factors. So for 5 factors, that would be 2^5, right?