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F5 Networks 301a Exam - Topic 1 Question 101 Discussion

Actual exam question for F5 Networks's 301a exam
Question #: 101
Topic #: 1
[All 301a Questions]

Refer to the Exhibit.

An LTM Specialist notices that two members in a pool are overloaded. To relive the existing members a fourth member (10.128.20.14) is brought up.

How many member will receive and process new connections?

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Suggested Answer: D

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Brittni
3 months ago
I’m not convinced, seems like 2 might still be overloaded.
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Trina
3 months ago
Definitely 4 members handling connections now!
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Rikki
3 months ago
Wait, are we sure the new member is actually active?
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Donte
4 months ago
I think only 3 will process new connections.
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Ivory
4 months ago
There are 4 members total now.
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Lynette
4 months ago
I feel like I saw something about this in the review materials. If two are overloaded and one is added, it might mean 3 can handle new connections.
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Wilbert
4 months ago
I’m a bit confused about how the new member integrates. Does it start processing immediately, or does it take time to balance?
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Carmen
4 months ago
I think from similar practice questions, only the active members in the pool process new connections. So, maybe it's just 3?
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Mila
5 months ago
I remember studying load balancing and how new members can help distribute traffic, but I'm not sure if all four will handle connections right away.
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Bettina
5 months ago
I've got this! The question states that the fourth member was brought up to relieve the existing overloaded members. So the new fourth member will be processing the new connections, along with the other three. The answer is A.
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Marjory
5 months ago
Okay, let's see. If two members were overloaded and a fourth member was added, that means there are now four members total. I think the answer is A.
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Tracey
5 months ago
Hmm, this looks like a tricky one. I'll need to carefully read through the details and think it through step-by-step.
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Chandra
5 months ago
Wait, I'm a bit confused. Does the question mean that the fourth member is now processing new connections, or that all four members are processing new connections? I need to re-read this.
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Natalie
10 months ago
Haha, trick question! The new member is obviously there to look pretty, not actually process any connections. I'm picking D, just to be safe.
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Alberto
8 months ago
I'm not so sure, I think the new member is just there for show. I'm sticking with D.
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Danica
9 months ago
I agree, I also think the new member is there to help process connections. A sounds like the right choice.
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Ben
9 months ago
I think the new member is there to help process connections, so I'm going with A.
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Stephen
10 months ago
This is a tricky one. I'm going to assume the new member is added to the load-balancing pool, so all four members will share the new connections. Gotta go with A on this one.
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Paris
9 months ago
Great, we're all on the same page then. A) 4 it is.
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Rodolfo
9 months ago
Yes, that makes sense. So, the answer is A) 4.
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Linn
10 months ago
I agree, adding the new member to the pool should distribute the new connections among all four members.
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Marjory
10 months ago
Wait, I thought the question said to relieve the existing members. Wouldn't that mean the new member would take on the load, leaving the other three to handle the new connections? C looks like the right answer to me.
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Meghann
8 months ago
D) 1
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Clemencia
9 months ago
C) 2
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Angelica
9 months ago
B) 3
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Makeda
9 months ago
A) 4
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Herman
10 months ago
Hmm, let's see. If we have two overloaded members and a new one is brought up, that should distribute the load across all four members, right? I'm going with option A.
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Beth
10 months ago
Yes, with four members, each should receive and process new connections.
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Ceola
10 months ago
I agree, adding a fourth member should distribute the load evenly.
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Kristeen
11 months ago
I'm not sure, but I think the answer is A) 4 as well. It makes sense to have all four members processing new connections.
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Theron
11 months ago
I agree with Keena, because the fourth member was brought up to relieve the overloaded members.
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Keena
11 months ago
I think the answer is A) 4.
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