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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set
cout<<*i<<" ";
}
return 0;
}
Suggested Answer: B
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34 comments · newest first
TE
Teri
11 months ago
No way, I thought it would output 2 3 4 5 6 7!
CA
Caprice
11 months ago
I thought it would include more numbers, weird!
CE
Celeste
11 months ago
Wait, how does it skip 2-7? Seems off.
LO
Louvenia
11 months ago
Totally agree, that's the right output!
BE
Bernardine
11 months ago
The program outputs: 0 1 8 9.
CU
Curtis
12 months ago
I’m confused about the order of elements in the output. I think it might be sorted, but I can't recall exactly how that affects the final result.
JA
Jaime
12 months ago
This reminds me of a practice question where we had to manipulate sets. I feel like the output should be the remaining elements after the erase operation.
HU
Hubert
12 months ago
I'm not entirely sure, but I remember something about lower_bound and upper_bound removing elements in a range.
BL
Blair
1 year ago
I think the set will only keep unique values, so duplicates from the vector won't affect the output.
JU
Julie
1 year ago
This is a good test of understanding set data structures and their methods. I'll make sure to carefully trace the logic to arrive at the correct answer.
EL
Elbert
1 year ago
I'm feeling pretty confident about this one. The set operations are straightforward, and I can see the final output taking shape as the code progresses.
AN
Antonio
1 year ago
Okay, I think I've got this. The key is understanding how the set is being modified by the insert and erase operations. I'll work through it systematically.
MA
Magda
1 year ago
This looks like a tricky one. I'll need to carefully step through the code and think through the set operations to figure out the output.
TE
Teresita
1 year ago
Hmm, I'm a bit confused by the set operations here. Let me re-read the question and try to visualize what's happening step-by-step.
RO
Rozella
1 year ago
I'm a bit confused by the options here. I'll need to carefully review the descriptions and think about the specific responsibilities of each listener to determine the right answer.
ZI
Zita
1 year ago
Okay, I think I've got a strategy here. I'll focus on the table aliases and join syntax options, since those seem like the most straightforward performance factors to evaluate.
MA
Martina
1 year ago
Hey, at least they're not using a linked list. That would be even more boring!
KA
Katina
1 year ago
User 3
JO
Jordan
1 year ago
User 2
MA
Mabel
1 year ago
User 1
JO
Joaquin
1 year ago
Wait, so this code is just a bunch of people playing with containers? I thought programming was supposed to be more exciting than that!
FA
Fabiola
1 year ago
D has got to be the right answer. The program is just playing with the vector and set, so the output should be the original integers in some order.
RO
Royal
1 year ago
Hmm, I think the answer is A. The program seems to be doing some weird set operations, but I'm not sure why the output would be 0 1 8 9.
LY
Lyndia
1 year ago
I'm pretty sure the answer is C. The set will only contain unique elements, and the erase operation will remove the range [2, 7], leaving 1, 6, 5, and 7.
JO
Johnson
1 year ago
Let's see the correct answer: B) program outputs: 2 3 4 5 6 7
TH
Theresia
1 year ago
Actually, I'm pretty sure it's B.
VI
Vince
1 year ago
No, I believe it's A.
EM
Emmett
1 year ago
I think the answer is C.
NI
Nickole
2 years ago
The correct answer is B. The program first creates a vector with the given integers, then creates a set from the vector, inserts the vector elements into the set, and finally erases the elements in the range [2, 7]. The resulting set contains the elements 2, 3, 4, 5, 6, 7, which are then printed.
NA
Naomi
1 year ago
That makes sense, the set is sorted and the elements in the range [2, 7] are erased.
NA
Naomi
1 year ago
B) program outputs: 2 3 4 5 6 7
HA
Haley
2 years ago
But the set will only contain unique elements, so I still think it's B.
LO
Lonny
2 years ago
I disagree, I believe the answer is C.
HA
Haley
2 years ago
I think the answer is B.