MENU
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout.setf(ios::oct, ios::basefield);
cout<<100<<" ";
cout.setf(ios::showbase);
cout<<100<<" ";
return 0;
}
Program outputs:
Suggested Answer: A
Get Premium CPP Questions
as Interactive Web-Based Practice Test or PDF
Real Exam Format
Detailed Explanations
Instant Access
Get Your Practice Test
10 comments · newest first
LU
Luke
11 months ago
I disagree, it should be 0x64 for the second one.
MO
Mose
11 months ago
Wait, why is it 144 and not 100?
DA
Dalene
12 months ago
I think it should show the base for the second output.
SH
Sheridan
12 months ago
Definitely not a compilation error!
GA
Gabriele
12 months ago
Outputs 144 0144
RO
Roslyn
1 year ago
I feel like there might be a compilation error because of the way the `setf` function is used, but I can't quite remember if that's correct.
OL
Olive
1 year ago
I practiced a similar question where we had to set different formats, and I think the output should be 144 for the first one and something with a prefix for the second.
MA
Mabel
1 year ago
I remember something about showing the base with `ios::showbase`, but I can't recall if it applies to the first output or the second one.
CA
Casey
1 year ago
I think the first output should be in octal since we set it to octal format, but I'm not sure what the actual value will be.
OZ
Ozell
1 year ago
Okay, I've got this. Documentary evidence is definitely required, so I'm going with option A. Can't go wrong with the basics.