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What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main ()
{
float f = 10.126;
cout< return 0; } Program outputs:
Suggested Answer: A
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12 comments · newest first
KA
Kaitlyn
3 months ago
I feel like it might be a compilation error, but I agree with you both.
GA
Gail
3 months ago
Yeah, setprecision(2) rounds it to two decimal places.
JE
Jenifer
3 months ago
I think it outputs 10.126 10.12.
SH
Shelia
3 months ago
It's B for sure, setprecision affects the output.
FE
Felicitas
3 months ago
Wait, why does it round down? That’s weird!
FR
Francesco
4 months ago
Definitely not a compilation error!
KA
Kate
5 months ago
I think it should be 10.126 10.13, right?
DE
Dell
5 months ago
The output will be 10.126 10.12.
QU
Quiana
6 months ago
I’m a bit confused; I thought setprecision only works with fixed notation, but this code doesn’t specify that. Could it lead to a different output?
KA
Kayleigh
6 months ago
I practiced a similar question, and I think the output will show the float with two decimal places, so it might be B.
FR
Francoise
6 months ago
I remember something about setprecision affecting the output, but I can't recall if it rounds or just truncates the number.
LI
Linwood
7 months ago
I think the code should compile fine since there are no syntax errors, but I'm not sure about the output formatting.